Neglecting the masses of the rope and pulleys, find the following. T₁ T₁ T₂ T3 T₂ (a) Find the required value of F. 218.1✔ N m (b) Find the tensions T₁, T2, and T3. (T3 indicates the tension in the rope which attaches the pulley to the ceiling.) = 218.1 = 436.1 = 436.1 N N N (c) Find the work done by the applied force in raising the object a distance of 1.70 m. 1.43 X Your response differs from the correct answer by more than 10%. Double check your calculations. kJ

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Topic Video
Question
**Title: Lifting an Object Using a Pulley System**

**Description:**
The system shown in the figure below is used to lift an object of mass \( m = 44.5 \) kg. A constant downward force of magnitude \( F \) is applied to the loose end of the rope such that the hanging object moves upward at constant speed. Neglecting the masses of the rope and pulleys, find the following.

**Figure Explanation:**
The figure depicts a pulley system with two pulleys and a rope. A mass \( m \) is attached to the lower pulley, and the rope is applied by a force \( \vec{F} \). The tensions in various segments of the rope are denoted as \( T_1 \), \( T_2 \), and \( T_3 \).

The diagram shows:
- \( T_1 \) as the tension in the rope segment below the lower pulley.
- \( T_2 \) as the tension in the rope segment between the pulleys.
- \( T_3 \) as the tension in the rope segment above the upper pulley. \( T_3 \) also indicates the tension that attaches the pulley to the ceiling.

**Problem Solving:**

**(a) Finding the required value of \( F \):**
- Given the system and the object’s mass \( m \), we calculate the required force \( F \) to maintain constant upward speed.

\[ F = 218.1 \, \text{N} \]

**(b) Finding the tensions \( T_1 \), \( T_2 \), and \( T_3 \):**
- For the system in equilibrium with the given mass \( m \), we find the tension values as follows:

\[ T_1 = 218.1 \, \text{N} \]
\[ T_2 = 436.1 \, \text{N} \]
\[ T_3 = 436.1 \, \text{N} \]

**(c) Finding the work done by the applied force in raising the object a distance of \( 1.70 \) m:**
- Work done, \( W \), by a force \( F \) over a distance \( d \) is calculated as \( W = F \cdot d \).

\[ \text{Calculated Work} = 1.43 \, \text{kJ} \]

**
Transcribed Image Text:**Title: Lifting an Object Using a Pulley System** **Description:** The system shown in the figure below is used to lift an object of mass \( m = 44.5 \) kg. A constant downward force of magnitude \( F \) is applied to the loose end of the rope such that the hanging object moves upward at constant speed. Neglecting the masses of the rope and pulleys, find the following. **Figure Explanation:** The figure depicts a pulley system with two pulleys and a rope. A mass \( m \) is attached to the lower pulley, and the rope is applied by a force \( \vec{F} \). The tensions in various segments of the rope are denoted as \( T_1 \), \( T_2 \), and \( T_3 \). The diagram shows: - \( T_1 \) as the tension in the rope segment below the lower pulley. - \( T_2 \) as the tension in the rope segment between the pulleys. - \( T_3 \) as the tension in the rope segment above the upper pulley. \( T_3 \) also indicates the tension that attaches the pulley to the ceiling. **Problem Solving:** **(a) Finding the required value of \( F \):** - Given the system and the object’s mass \( m \), we calculate the required force \( F \) to maintain constant upward speed. \[ F = 218.1 \, \text{N} \] **(b) Finding the tensions \( T_1 \), \( T_2 \), and \( T_3 \):** - For the system in equilibrium with the given mass \( m \), we find the tension values as follows: \[ T_1 = 218.1 \, \text{N} \] \[ T_2 = 436.1 \, \text{N} \] \[ T_3 = 436.1 \, \text{N} \] **(c) Finding the work done by the applied force in raising the object a distance of \( 1.70 \) m:** - Work done, \( W \), by a force \( F \) over a distance \( d \) is calculated as \( W = F \cdot d \). \[ \text{Calculated Work} = 1.43 \, \text{kJ} \] **
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
First law of motion
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON