Neglecting the masses of the rope and pulleys, find the following. T₁ T₁ T₂ T3 T₂ (a) Find the required value of F. 218.1✔ N m (b) Find the tensions T₁, T2, and T3. (T3 indicates the tension in the rope which attaches the pulley to the ceiling.) = 218.1 = 436.1 = 436.1 N N N (c) Find the work done by the applied force in raising the object a distance of 1.70 m. 1.43 X Your response differs from the correct answer by more than 10%. Double check your calculations. kJ

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**Title: Lifting an Object Using a Pulley System**

**Description:**
The system shown in the figure below is used to lift an object of mass \( m = 44.5 \) kg. A constant downward force of magnitude \( F \) is applied to the loose end of the rope such that the hanging object moves upward at constant speed. Neglecting the masses of the rope and pulleys, find the following.

**Figure Explanation:**
The figure depicts a pulley system with two pulleys and a rope. A mass \( m \) is attached to the lower pulley, and the rope is applied by a force \( \vec{F} \). The tensions in various segments of the rope are denoted as \( T_1 \), \( T_2 \), and \( T_3 \).

The diagram shows:
- \( T_1 \) as the tension in the rope segment below the lower pulley.
- \( T_2 \) as the tension in the rope segment between the pulleys.
- \( T_3 \) as the tension in the rope segment above the upper pulley. \( T_3 \) also indicates the tension that attaches the pulley to the ceiling.

**Problem Solving:**

**(a) Finding the required value of \( F \):**
- Given the system and the object’s mass \( m \), we calculate the required force \( F \) to maintain constant upward speed.

\[ F = 218.1 \, \text{N} \]

**(b) Finding the tensions \( T_1 \), \( T_2 \), and \( T_3 \):**
- For the system in equilibrium with the given mass \( m \), we find the tension values as follows:

\[ T_1 = 218.1 \, \text{N} \]
\[ T_2 = 436.1 \, \text{N} \]
\[ T_3 = 436.1 \, \text{N} \]

**(c) Finding the work done by the applied force in raising the object a distance of \( 1.70 \) m:**
- Work done, \( W \), by a force \( F \) over a distance \( d \) is calculated as \( W = F \cdot d \).

\[ \text{Calculated Work} = 1.43 \, \text{kJ} \]

**
Transcribed Image Text:**Title: Lifting an Object Using a Pulley System** **Description:** The system shown in the figure below is used to lift an object of mass \( m = 44.5 \) kg. A constant downward force of magnitude \( F \) is applied to the loose end of the rope such that the hanging object moves upward at constant speed. Neglecting the masses of the rope and pulleys, find the following. **Figure Explanation:** The figure depicts a pulley system with two pulleys and a rope. A mass \( m \) is attached to the lower pulley, and the rope is applied by a force \( \vec{F} \). The tensions in various segments of the rope are denoted as \( T_1 \), \( T_2 \), and \( T_3 \). The diagram shows: - \( T_1 \) as the tension in the rope segment below the lower pulley. - \( T_2 \) as the tension in the rope segment between the pulleys. - \( T_3 \) as the tension in the rope segment above the upper pulley. \( T_3 \) also indicates the tension that attaches the pulley to the ceiling. **Problem Solving:** **(a) Finding the required value of \( F \):** - Given the system and the object’s mass \( m \), we calculate the required force \( F \) to maintain constant upward speed. \[ F = 218.1 \, \text{N} \] **(b) Finding the tensions \( T_1 \), \( T_2 \), and \( T_3 \):** - For the system in equilibrium with the given mass \( m \), we find the tension values as follows: \[ T_1 = 218.1 \, \text{N} \] \[ T_2 = 436.1 \, \text{N} \] \[ T_3 = 436.1 \, \text{N} \] **(c) Finding the work done by the applied force in raising the object a distance of \( 1.70 \) m:** - Work done, \( W \), by a force \( F \) over a distance \( d \) is calculated as \( W = F \cdot d \). \[ \text{Calculated Work} = 1.43 \, \text{kJ} \] **
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