needed for this question. The free energy change for the following reaction at 25 °C, when [Zn]= 6.08×10 M and [Cu]=1.11 M, is 225 kJ Zn (6.08×10 M) + Cu(s) Zn(s) + Cu"(1.11 M) AG 225 kJ What is the cell potential for the reaction as written under these conditions? Answer: Would this reaction be spontaneous in the forward or the reverse direction? Retry Entire Group 1 more group attempt remaining Submit Answer

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IReferences
Use the References to access mportant values if needed for this question.
The free energy change for the following reaction at 25 °C, when [Zn =6.08×10 M and [Cu=1.11 M, is 225 kJ
T:
Zn"(6.08×10 M) - Cu(s)-
→ Zn(s) -Cu (1.11 M) AG=225 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
Would this reaction be spontaneous n the forward or the reverse direction?
Retry Entire Group
1more group attempt remaining
Submit Answer
Transcribed Image Text:IReview Topicsi IReferences Use the References to access mportant values if needed for this question. The free energy change for the following reaction at 25 °C, when [Zn =6.08×10 M and [Cu=1.11 M, is 225 kJ T: Zn"(6.08×10 M) - Cu(s)- → Zn(s) -Cu (1.11 M) AG=225 kJ What is the cell potential for the reaction as written under these conditions? Answer: Would this reaction be spontaneous n the forward or the reverse direction? Retry Entire Group 1more group attempt remaining Submit Answer
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