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1. Consider the following: Zn²+2e-→ Zn -0.76 V Cr²+2e- Cr -0.91 V What is the Standard cell potential for the reaction ? (a) 1.67 V (b) -1.67V (c) -0.15 V (d) 0.15V Calling:

1. Consider the following: Zn²+2e-→ Zn -0.76 V Cr²+2e- Cr -0.91 V What is the Standard cell potential for the reaction ? (a) 1.67 V (b) -1.67V (c) -0.15 V (d) 0.15V Calling:

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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## Electrochemistry: Calculating Standard Cell Potential ### Task 1: Consider the following half-reactions: - \( \text{Zn}^{2+} + 2e^- \rightarrow \text{Zn} \) - Potential: \(-0.76 \, \text{V}\) - \( \text{Cr}^{2+} + 2e^- \rightarrow \text{Cr} \) - Potential: \(-0.91 \, \text{V}\) **Question:** What is the Standard cell potential for the reaction? Options: (a) \( 1.67 \, \text{V} \) (b) \(-1.67 \, \text{V} \) (c) \(-0.15 \, \text{V} \) (d) \( 0.15 \, \text{V} \) ### Explanation: To calculate the standard cell potential, use the formula: \[ E_{\text{cell}} = E_{\text{cathode}} - E_{\text{anode}} \] Consider which half-reaction will act as the cathode and which will act as the anode in order to determine \( E_{\text{cell}} \).
Transcribed Image Text:## Electrochemistry: Calculating Standard Cell Potential ### Task 1: Consider the following half-reactions: - \( \text{Zn}^{2+} + 2e^- \rightarrow \text{Zn} \) - Potential: \(-0.76 \, \text{V}\) - \( \text{Cr}^{2+} + 2e^- \rightarrow \text{Cr} \) - Potential: \(-0.91 \, \text{V}\) **Question:** What is the Standard cell potential for the reaction? Options: (a) \( 1.67 \, \text{V} \) (b) \(-1.67 \, \text{V} \) (c) \(-0.15 \, \text{V} \) (d) \( 0.15 \, \text{V} \) ### Explanation: To calculate the standard cell potential, use the formula: \[ E_{\text{cell}} = E_{\text{cathode}} - E_{\text{anode}} \] Consider which half-reaction will act as the cathode and which will act as the anode in order to determine \( E_{\text{cell}} \).
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