I am confused as to why "A distance 2h/3 above the floor" is the answer. Did it use the law of conservation of energy: 1/2mvi^2+mgh+1/2kxi^2+Wnc=1/2mvf^2+mgh+1/2xf^2?I was somehow able to answer and come up with an answer: 2h/3 a distance 2h/3 above the floor. However, I am not sure if I did the right thing. mgh + Wnc = mghfmgh/3 + mgh = mghf2mgh/3 =mghf2h/3 = hf Need help with concepts in the problem below!In this problem, we will consider the following situation as depicted in the diagram(Figure 1) : A block of mass m slides at a speed v along a horizontal, smooth table. It nextslides down a smooth ramp, descending a height h, and then slides along a horizontalrough floor, stopping eventually. Assume that the block slides slowly enough so that itdoes not lose contact with the supporting surfaces (table, ramp, or floor).You will analyze the motion of the block at different moments using the law ofconservation of energy.Vr = 0Part BSuppose the potential energy of the block at the table is given by mgh|3. This impliesthat the chosen zero level of potential energy is .a distance h/3 above the floora distance h/3 below the floora distance 2h/3 above the floora distance 2h/3 below the flooron the floorMastering Physics lists the correct answer at "A distance 2h/3 above the floor"But why is that the case? Could someone help explain this?

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Answered: Need help with concepts in the problem…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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I am confused as to why "A distance 2h/3 above the floor" is the answer. Did it use the law of conservation of energy: 1/2mvi^2+mgh+1/2kxi^2+Wnc=1/2mvf^2+mgh+1/2xf^2?

I was somehow able to answer and come up with an answer: 2h/3 a distance 2h/3 above the floor. However, I am not sure if I did the right thing.

mgh + Wnc = mghf

mgh/3 + mgh = mghf

2mgh/3 =mghf

2h/3 = hf

Need help with concepts in the problem below!
In this problem, we will consider the following situation as depicted in the diagram
(Figure 1) : A block of mass m slides at a speed v along a horizontal, smooth table. It next
slides down a smooth ramp, descending a height h, and then slides along a horizontal
rough floor, stopping eventually. Assume that the block slides slowly enough so that it
does not lose contact with the supporting surfaces (table, ramp, or floor).
You will analyze the motion of the block at different moments using the law of
conservation of energy.
Vr = 0
Part B
Suppose the potential energy of the block at the table is given by mgh|3. This implies
that the chosen zero level of potential energy is .
a distance h/3 above the floor
a distance h/3 below the floor
a distance 2h/3 above the floor
a distance 2h/3 below the floor
on the floor
Mastering Physics lists the correct answer at "A distance 2h/3 above the floor"
But why is that the case? Could someone help explain this?

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