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na study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6991 subjects randomly selected from an online group involved with ears. There were 1319 surveys returned. Use a 0.01 significance level to est the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. dentify the null hypothesis and alternative hypothesis. О в. Но: р<0.2 H:p= 0.2 DA. Ho: p=0.2 H:p>0.2 DC. Ho: p= 0.2 OD. Ho: p>0.2 H;:p=0.2 H:p#0.2 DE. Ho: p#0.2 OF. Ho: p=0.2 H1:p=0.2 H1:p<0.2 he test statistic is z=. Round to two decimal places as needed.) he P-value is. Round to three decimal places as needed.) cecause the P-value is the significance level V the null hypothesis. There is V evidence to support the claim that the return rate is less than 20%.

na study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6991 subjects randomly selected from an online group involved with ears. There were 1319 surveys returned. Use a 0.01 significance level to est the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. dentify the null hypothesis and alternative hypothesis. О в. Но: р<0.2 H:p= 0.2 DA. Ho: p=0.2 H:p>0.2 DC. Ho: p= 0.2 OD. Ho: p>0.2 H;:p=0.2 H:p#0.2 DE. Ho: p#0.2 OF. Ho: p=0.2 H1:p=0.2 H1:p<0.2 he test statistic is z=. Round to two decimal places as needed.) he P-value is. Round to three decimal places as needed.) cecause the P-value is the significance level V the null hypothesis. There is V evidence to support the claim that the return rate is less than 20%.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6991 subjects randomly selected from an online group involved with ears. There were 1319 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the nullI hypothesis and alternative hypothesis. О А. Но: р30.2 О В. Но: р<0.2 H1:p= 0.2 H1:p>0.2 Ос. Но: р-0.2 H1: p#0.2 D. Ho: р> 0.2 H1:p=0.2 O E. Ho: p+0.2 H1:p= 0.2 O F. Ho: p= 0.2 H1:p<0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.
Transcribed Image Text:In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6991 subjects randomly selected from an online group involved with ears. There were 1319 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the nullI hypothesis and alternative hypothesis. О А. Но: р30.2 О В. Но: р<0.2 H1:p= 0.2 H1:p>0.2 Ос. Но: р-0.2 H1: p#0.2 D. Ho: р> 0.2 H1:p=0.2 O E. Ho: p+0.2 H1:p= 0.2 O F. Ho: p= 0.2 H1:p<0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.
Expert Solution
Step 1

Given :

H0 : p ≥ 0.2H1 : p< 0.2

This is a lower tailed test,

p^ = xn

p^ = 13196991

p^ = 0.1887

α = 0.01

σp^ = p×1-pn

σp^ = 0.2×1-0.26991

σp^ = 0.0048

 

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