Step 1) Using a 24 hole-well plate, put 4 drops of HCl in 12 wells each. Make sure yourdrops are the same size by dropping from a straight vertical position. Put 1 drop ofindicator into each well. Into those same 12 wells, put increasing drops of NaOH intoeach well. (1 drop for well #1, 2 drops for well #2... 12 drops for well # 12.) Set up adata table showing the pH level in each of the wells for this titration.Question: Write out a chemical equation for this reaction. (The chemical equation, forexample is NaOH + HCl → HOH+ NaCl.) Explain what equivalence point is, what thepH is at the equivalence point in this reaction and why the pH is what it is. Keep this as akey to compare the rest of the titrations to. You can find the titration curve in the textbook or from a Google search.

Sodium hydroxide + Hydrochloride acid -------> Sodium chloride + Water The point at which exactly…

n Write out a chemical equation for this reaction. (The chemical equation, for e is NaOH+ HCI → HOH + NaCl.) Explain what equivalence point is, what the t the equivalence point in this reaction and why the pH is what it is. Keep this as a compare the rest of the titrations to. You can find the titration curve in the text - from a Google search.

n Write out a chemical equation for this reaction. (The chemical equation, for e is NaOH+ HCI → HOH + NaCl.) Explain what equivalence point is, what the t the equivalence point in this reaction and why the pH is what it is. Keep this as a compare the rest of the titrations to. You can find the titration curve in the text - from a Google search.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Part C – Acid–base and solubility equilibria 1. Rinse 4 regular size test tubes and a 10 mL measuring cylinder thoroughly with water. Number the test-tubes from 1 to 4 in a test tube rack. 2. Into each of test tubes 1 – 3 put a small amount of solid benzoic acid (put the same amount – about the size of a pea – in each test tube). 3. Add 2 mL (use the measuring cylinder) of water to tube 1 and shake to mix the contents. 4. Add 2 mL (measuring cylinder) of 2 M HNO3 to tube 2 and shake to mix the contents. 5. Rinse the measuring cylinder with water, then use it to add 2 mL of 2 M NaOH to tube 3 and shake for about 10 seconds to mix the contents. Rinse the measuring cylinder. 6. Pour about half of the solution from tube 3 into tube 4, than add 2 mL of 2 M HNO3 to tube 4. 7. Allow the test tubes to stand for 2 or 3 minutes then record the appearance of the mixtures in each test tube. 8. Answer the questions on the results page relating to this equilibrium system.
Can you confidently determine if the molarities are accurate? Explain why or why not.
Buffers pH
During a titration, it is found that 59.5 mL of a solution of NaOH is needed to neutralize a solution that contains 1.69 g HCL. What is the concentration of the NaOH solution? a.) 0.3535m b.) 0. 6869m c.) 0. 7790m d.) 0. 6051m e.) 1.055m
Can you please do A and B thank you!
2. In the second titration, the molar mass of an unknown monoprotic acid is calculated. If 0.100 grams of unknown solid are dissolved in water and titrated with 4.68 mL of the NaOH, what is the molar mass of the solid? HINTS: Molar mass is grams / moles. We have grams from the weighed mass, we can calculate moles of acid from the titration. Monoprotic means that it produces 1 H+ per molecule. This means that our moles of NaOH added and moles of acid are the same. You will need to use your concentration of NaOH from the previous question Which is 0.1186
Please don't provide hand written solution.....
What chemical would have to be in the same solution as CHO2- in order to form a buffer? Question 9 options: CO2- O2- HCHO2 CO22-
Exactly 10.66 ml of 0.066 M strong acid is added to a 30.00 ml. sample of a 0.068 M weak base solution. What is the pH at this point in the titration? K for the base is 2.51x10-5. REPORT YOUR ANSWER TO 2 DECIMAL PLACES. DO NOT INCLUDE UNITS. Type your answer....
Please type this, do not write it on a paper.
someone please help me with these questions! ?
Q6 chapter 15 titration: multimedia activities Solve Asap please