N-methyltriphenylmethanamine Methanamine + CH,- NH2 c-NH-CH, HCI 31.057 36.461 279.775 273.372

Chemistry
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Chapter1: Chemical Foundations
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Figure 3 shows a substitution reaction between triphenylmethyl chloride and an excess of the base methanamine. What is the minimum mass of this amine required to produce 5.000 grams of the organic product N-methyltriphenylmethanamine? Molar masses are given in Figure 3. [Round the answer to three decimal places. Do not type in the unit. Use a decimal point.] *

Do you need to add imidazole to the reaction mixture used in this question to absorb the hydrogen chloride gas produced during the reaction?

N-methyltriphenylmethanamine
Methanamine
-c-CI
+ CH,- NH2
-c-NH-CH,
HCI
31.057
36.461
279.775
273.372
Transcribed Image Text:N-methyltriphenylmethanamine Methanamine -c-CI + CH,- NH2 -c-NH-CH, HCI 31.057 36.461 279.775 273.372
Expert Solution
Step 1

Amine are functional groups containing -NH2 groups.

Amine when taken 31.057 g produces 273.372 grams of organic product N-methyltriphenylmethanamine. 

Therefore, to obtain 5 g of organic product N-methyltriphenylmethanamine, amine required

= ( 5 * 31.057 ) / 273.372 grams

= 0.568 grams

 

Therefore, required minimum amount of amine is 0.568 grams. 

           

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