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N³ = 2₁ +252 +3 NO³ = 120° N ³Ã³ = 2 ñ +2ñ₂+Û³ NOB = 120°

N³ = 2₁ +252 +3 NO³ = 120° N ³Ã³ = 2 ñ +2ñ₂+Û³ NOB = 120°

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter1: Basic Modes Of Heat Transfer
Section: Chapter Questions
Problem 1.71P: 1.71 The thermal conductivity of silver at 212°F is 238 Btu/h ft °F. What is the conductivity in SI...
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I had a theoretical question about attitude determination. In the attached images, I gave two axis and angles. The coefficient of the axes are the same and the angles are the same. The only difference is the vector basis. Lets say there is a rotation going from n hat to b hat. Then, you introduce a intermediate rotation s hat. So, I want to know if the DCM produced from both axis and angles will be the same or not. Does the vector basis affect the numerical value of the DCM? The DCM formula only cares about the coefficient of the axis and the angle. So, they should be the same right?

N³ = 2₁ +252 +3 NO³ = 120°
Transcribed Image Text:N³ = 2₁ +252 +3 NO³ = 120°
N ³Ã³ = 2 ñ +2ñ₂+Û³ NOB = 120°
Transcribed Image Text:N ³Ã³ = 2 ñ +2ñ₂+Û³ NOB = 120°
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