n = 6559 CH4 → moles 40.84 0.0821 R= T= 25% +273 = 298 K X 16. Methane, CH4, is being considered for use as an alternative automotive fuel to replace gasoline. One gallon of gasoline could be replaced by 655 g of CH4. What is the volume of this much methane at 25 °C and 745 tom? PV=nRT 655g CHy ImaCHy = 46.84 Півондени 745 760 ON torr 1 atm = 0.98 atm 98 atm V = ? 0.98 am)(u) = 40.84 moles) (0.82101) (298k) 0.98 atm98 U= 0.9604 V = 9791.996०७७ 0.9604 0.9604 17. Iodine, I₂, is a solid at room temperature but sublimes (converts from a solid into a gas) when w temperature in a 73.3-mL bulb that contains 0.292 g of 1₂ vapor al P= 0.462 atm = 10195.74767 101961 CH₂
n = 6559 CH4 → moles 40.84 0.0821 R= T= 25% +273 = 298 K X 16. Methane, CH4, is being considered for use as an alternative automotive fuel to replace gasoline. One gallon of gasoline could be replaced by 655 g of CH4. What is the volume of this much methane at 25 °C and 745 tom? PV=nRT 655g CHy ImaCHy = 46.84 Півондени 745 760 ON torr 1 atm = 0.98 atm 98 atm V = ? 0.98 am)(u) = 40.84 moles) (0.82101) (298k) 0.98 atm98 U= 0.9604 V = 9791.996०७७ 0.9604 0.9604 17. Iodine, I₂, is a solid at room temperature but sublimes (converts from a solid into a gas) when w temperature in a 73.3-mL bulb that contains 0.292 g of 1₂ vapor al P= 0.462 atm = 10195.74767 101961 CH₂
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
16?

Transcribed Image Text:P= 0.98 atmo
?
n = 655g CH4 -) moles 40.84
R= 0.0821
= K
x 16. Methane, CH4, is being considered for use as an alternative automotive fuel to replace gasoline. One gallon of
gasoline could be replaced by 655 g of CH4. What is the volume of this much methane at 25 °C and 745 torr?
PV=nRT
745 torr 1 atm
6.98 am)(u) = 16.84 moles) (0.821 m) (298k)
0.98
0.98 atm98
U=
0.9604 V = 9791.996066
0.9604
0.9604
= 10195.74767
10196L CH
17. Iodine, I2, is a solid at room temperature but sublimes (converts from a solid into a gas) when warmed. What is the
temperature in a 73.3-mL bulb that contains 0.292 g of 1₂ vapor at a pressure of 0.462 atm? PART
0.462 atm
(0.462 am)(0.07330)=6.0115065122m) (082) (1) 73.3m²| IL
0.03 38646-9.445705162×10³T
1000
P=
V= 73.3mL) L 0.0733L
n = 0.2929 1₂ -0.0011505122 mois 9.445705162x105
R=0.0821
T= ?
T= 358.5184951
18. How many grams of gas are present in 0.100 L of CO₂ at 307 torr and 26 °C?
359 K
PV=nRT
(040am)(.lcoL) tn[,0,0%2 (240)
P= 0.40 T = 299k
24.54790
0.0404
24.5479
The triple point temperature: -75 °C
The state of the gas at -65°C and 9,000kPa: liquid
24.5479 = 0.001645762
6.00 164578 mois Co> 44.01960₂
mois
Pressure (kPa)
1,000,000-
100,000-
V=100 L
n= ? grams
R = 0.0821
-0.072 g CO₂
19. An unknown gas effuses 1.66 times more rapidly than CO₂. What is the molar mass of the unknown gas?
Rate A
√mmB
(1536 ) (144)
니니
44g/m01.03
Bate B mmA
15.94g/mc) CH4
X
2.76
10,000-
1000-
6559 CH4 ImaCHy = 40.84
Півондени
100-
445705162x10-5
Solid
unknown ges S CH4
20. Arrange each the following set of compounds in order of increasing boiling point temperature and explain your
the arrangement of
reasoning: HCl, H₂O, SiH4
Stronger the bend +
The
boiling point depends on
there fore the
Si Hy< Hc< H₂0
higher the boiling paint will be.
10-
-100 -75-50
H₂o has the highest boiling point because it has hydrogen bonds and hydre
bonds are the strongest intermolecular
which in this case have the Second
Phase
21. Use the following
bond of a molecule: HCI is polar coldier
strongest bond / second strongest highest ba
Paint. S. Hy has the lowest boiling paint
BOTGR covalent bonds w
diagram for carbon dioxide to indicate: en boit
the triple point pressure: 100K Pa
Liquid
0 Tc
Temperature ("C)
760 torr
26°C+273=299K
=0.98 atm
50
307 tom latm
SCF
0.292932 | Mol 1₂ = 0.001
1253.89 22 90512
= 0.0733
L
100
760 forr = 0.404
atm
at +65°C and 11,000 kPa: Supercrit
fiu
(sc
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