In C.AJ -Kt + ln [A.o]. t1/₂ = 0.693 K 'In = KE CAJO. CAJE EAJo 100./. CAJO [A] += left it = ln [AG] K [100] [s]t .In. K= 0.693 t11₂ =kt CAJO K= In [AE]. t Formulas Problem: Na-24 has a half life of 15 hours. How much of a 20.09. Sample would remain after decaying for 60 hours? Plz explain step by step using the formulas..
In C.AJ -Kt + ln [A.o]. t1/₂ = 0.693 K 'In = KE CAJO. CAJE EAJo 100./. CAJO [A] += left it = ln [AG] K [100] [s]t .In. K= 0.693 t11₂ =kt CAJO K= In [AE]. t Formulas Problem: Na-24 has a half life of 15 hours. How much of a 20.09. Sample would remain after decaying for 60 hours? Plz explain step by step using the formulas..
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![. In C.AJ = - kt.tln [A.o].
t¹/₂ = 0.693
K
In
= KE
•1• [A]o⋅=⋅· 100 ·/.
[A] + = left
.
CAJO.
CAJE
In.
[100]
[s] t
=.kt
K= 0.693
t¼½₂
CAJO
t = |n² Ch
t = ln [AG]
·K
CAJO
K= In [At].
t
Formulas
Problem:
Na-24 has a half life of 15 hours. How much of a 20.09.
·Sample would remain after decaying for 60 hours?
Plz explain step by step. using the formulas..](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F08bb2a94-da17-43f2-90ab-4ad444df37b3%2Fd1c5faad-f3c3-45e6-9542-a6b89748d523%2Fxejoe7k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:. In C.AJ = - kt.tln [A.o].
t¹/₂ = 0.693
K
In
= KE
•1• [A]o⋅=⋅· 100 ·/.
[A] + = left
.
CAJO.
CAJE
In.
[100]
[s] t
=.kt
K= 0.693
t¼½₂
CAJO
t = |n² Ch
t = ln [AG]
·K
CAJO
K= In [At].
t
Formulas
Problem:
Na-24 has a half life of 15 hours. How much of a 20.09.
·Sample would remain after decaying for 60 hours?
Plz explain step by step. using the formulas..
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