n 220/0 Vrms 220-120 Vrms 220/120 V 292 292 202 S = 14.24angle11.3⁰ kVA S 19.24angle16.3⁰ kVA = (8 +j2) Ω S = 14.24angle30.3⁰ kVA OS = 21.24angle11.3⁰ kVA (8 + 12) Ω (8+j2) 22 Determine the complex power supplied by the three-phase source. Hint: There are three complex power values. ON
n 220/0 Vrms 220-120 Vrms 220/120 V 292 292 202 S = 14.24angle11.3⁰ kVA S 19.24angle16.3⁰ kVA = (8 +j2) Ω S = 14.24angle30.3⁰ kVA OS = 21.24angle11.3⁰ kVA (8 + 12) Ω (8+j2) 22 Determine the complex power supplied by the three-phase source. Hint: There are three complex power values. ON
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Related questions
Question
100%
Determine the complex power supplied by the three-phase source.
Hint: There are three complex power values.

Transcribed Image Text:n
220/0 Vrms
220-120 Vrms
220/120 V
292
292
202
S = 14.24angle11.3⁰ kVA
S 19.24angle16.3⁰ kVA
=
(8 +j2) Ω
S = 14.24angle30.3⁰ kVA
OS = 21.24angle11.3⁰ kVA
(8 + 12) Ω
(8+j2) 22
Determine the complex power supplied by the three-phase source.
Hint: There are three complex power values.
ON
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