MOLAR VIEW T03/S11 If a sample of SOz is found to contain 5.29 mol of S atoms how many moles of O atoms are present? Molar Mass (g/mol) SO3 S atom O atom 80.058 32.066 15.999 Avogadro's No. (mol1) 6.022x1023 the tolerance is +/-2%
MOLAR VIEW T03/S11 If a sample of SOz is found to contain 5.29 mol of S atoms how many moles of O atoms are present? Molar Mass (g/mol) SO3 S atom O atom 80.058 32.066 15.999 Avogadro's No. (mol1) 6.022x1023 the tolerance is +/-2%
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given that,
Moles of S atom in SO3 sample is= 5.29 mol
From Avogadro’s law, 1 mol of SO3 sample will have 1 mol S and 3 moles of O-atoms.
[Also, from given data of molar masses, it can be confirmed that:
1 mole SO3 =80.058 g
1 mol S= 32.066 g
3 mol O =3×15.999 g =47.997
Adding the two values : 1 mol S+ 3 mol O = 32.066 g+ 47.997 g= 80.063 g (molar mass of SO3 )
The difference between the two molar masses are:
80.063 g-80.058g =0.005 g
which is very very less than 1 % (0.8 g) of the original molar mass, and so it can be ignored.
Thus, it is proved that 1 mol of SO3 has 1 mol S and 3 mol O-atoms.]
Hence,
The moles of SO3 = mole of S-atom = 5.29 mol
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