from 9 0₂ lost (#2) → mol O₂ lost from mol O₂ lost (#3)→ mol KC103 from mol KC10₂ (#4) →g KC103² 3. Stoichiometry 4. Stoichiometry 5. Stoichiometry
from 9 0₂ lost (#2) → mol O₂ lost from mol O₂ lost (#3)→ mol KC103 from mol KC10₂ (#4) →g KC103² 3. Stoichiometry 4. Stoichiometry 5. Stoichiometry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Weight of O2 gas lost was 0.279g O2

Transcribed Image Text:3. Stoichiometry
4. Stoichiometry
5. Stoichiometry
from 9 0₂ lost (#2)→ mol O₂ lost
from mol O₂ lost (#3)→ mol KC103
from mol KC10₂3 (#4) →g KC103´
Expert Solution

Step 1
From the mass of O2 gas lost we can figure out moles of O2.
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