**MOLAR VIEW T03/S11****Question:** How many moles of C atoms are present in 0.683 mol of CO molecules?[Input Box for Answer](Note: The tolerance is +/-2%)---**Molar Mass (g/mol):**- CO: 28.01- C atom: 12.011- O atom: 15.999**Avogadro's Number (mol⁻¹):** 6.022×10²³---**Explanation:**This question is about calculating the number of moles of carbon (C) atoms in a given amount of carbon monoxide (CO) molecules. Since 1 mole of CO contains 1 mole of C atoms, the number of moles of C atoms will be the same as the number of moles of CO molecules, which is 0.683 mol in this example. The information provided includes the molar masses of CO, C, and O, as well as Avogadro's number for comprehending molecular and atomic calculations. The tolerance indicates that small variations in the calculated answers are acceptable within a specific range.

Molecular formula of Carbon Monoxide is CO . And each CO molecule contains 1 carbon atom. Thus, each mole of CO contains 1 moles of carbon atom. We have, Moles of Carbon Monoxide = 0.683 moleMoles of C = Moles of CO × 1 mol C1 mol CO Moles of C = 0.683 mol CO × 1 mol C1 mol CO Moles of C atom = 0.683 mol Therefore, 0.683 mol of carbon atoms are present in 0.683 mole of Carbon Monoxide ( CO).

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Chemistry

How many moles of C atoms are present in 0.683 mol of Co molecules?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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