MISSED THIS? Read Section 15.6 (Pages 656 - 661); Watch KCV 15.6, IWE 15.9.Consider this overall reaction, which is experimentally observed to be second order in X and first order in Y: X + Y→ XY Part A Does the reaction occur in a single step which X and Y collide? Match the words in the left column to the appropriate blanks in the sentences on the right. contradicts The reaction rate = k[X][Y]² imply a rate law of rate = k[X]²[Y] does does not aligns with rate = k[X][Y] Reset Help occur in a single step in which X and Y collide because this would which the observed rate law of

Chemistry: The Molecular Science
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ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 71QRT
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Consider this overall reaction, which is experimentally observed to be second order in X and first order in Y:
X+Y→XY

Does the reaction occur in a single step in which XX and YY collide?    

 

    

 

MISSED THIS? Read Section
15.6 (Pages 656 - 661) ; Watch KCV 15.6, IWE
15.9.Consider this overall reaction, which is
experimentally observed to be second order in X
and first order in Y:
X + Y→ XY
Part A
Does the reaction occur in a single step in which X and Y collide?
Match the words in the left column to the appropriate blanks in the sentences on the right.
contradicts
The reaction
rate = k[X][Y]²
imply a rate law of
rate = k[X]²[Y]
does
does not
aligns with
= k[X][Y]
rate =
Reset Help
occur in a single step in which X and Y collide because this would
which
the observed rate law of
"
Transcribed Image Text:MISSED THIS? Read Section 15.6 (Pages 656 - 661) ; Watch KCV 15.6, IWE 15.9.Consider this overall reaction, which is experimentally observed to be second order in X and first order in Y: X + Y→ XY Part A Does the reaction occur in a single step in which X and Y collide? Match the words in the left column to the appropriate blanks in the sentences on the right. contradicts The reaction rate = k[X][Y]² imply a rate law of rate = k[X]²[Y] does does not aligns with = k[X][Y] rate = Reset Help occur in a single step in which X and Y collide because this would which the observed rate law of "
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