step elementary reaction rate constant 1 NO₂(g) + F₂(g) → NO₂F(g) + F(g) k₁ 2 F (g) + NO₂(g) - NO₂F (g) k₂ Suppose also k₁k2. That is, the first step is much faster than the second. Write the balanced chemical equation for the overall chemical reaction: Write the experimentally- observable rate law for the overall chemical reaction. rate = k Note: your answer should not contain the concentrations of any intermediates. Express the rate constant k for the overall chemical reaction in terms of K₁, K2, and (if necessary) the rate constants k-1 and k-2 for the reverse of the two elementary reactions in the mechanism. k = U 0-0 믐 010 X C

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Chapter1: Chemical Foundations
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step
elementary reaction
rate constant
1 NO₂(g) + F₂(g)
→
k₁
2
F (g) + NO₂(g) NO₂F (g)
k₂
Suppose also k₁k2. That is, the first step is much faster than the second.
Write the balanced
chemical equation for the
overall chemical reaction:
Write the experimentally-
observable rate law for the
overall chemical reaction.
rate = k
Note: your answer should
not contain the
concentrations of any
intermediates.
Express the rate constant
k for the overall chemical
reaction in terms of K₁, K2,
and (if necessary) the rate
constants k-1 and k-2 for
the reverse of the two
elementary reactions in
the mechanism.
k = 0
NO₂F(g) + F(g)
0-0
믐
010
X
Transcribed Image Text:step elementary reaction rate constant 1 NO₂(g) + F₂(g) → k₁ 2 F (g) + NO₂(g) NO₂F (g) k₂ Suppose also k₁k2. That is, the first step is much faster than the second. Write the balanced chemical equation for the overall chemical reaction: Write the experimentally- observable rate law for the overall chemical reaction. rate = k Note: your answer should not contain the concentrations of any intermediates. Express the rate constant k for the overall chemical reaction in terms of K₁, K2, and (if necessary) the rate constants k-1 and k-2 for the reverse of the two elementary reactions in the mechanism. k = 0 NO₂F(g) + F(g) 0-0 믐 010 X
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