Facebook: A study showed that two years ago, the mean time spent per visit to Facebook was 20.8 minutes, Assume the standard devlation is o= 8.0minutes. Suppose that a simple random sample of 107 visits was selected this year and has a sample mean of x= 18.8 minutes. A social scientist is interestedto know whether the mean time of Facebook visits has decreased. Use the a=0.10 level of significance and the critical value method with the table.(a) State the appropriate null and alternate hypotheses.(b) Compute the value of the test statistic.(c) State a conclusion. Use the a = 0.10 level of significance. Part 4 of 5Determine whether to reject H(Choose one)v the null hypothesis, H at the a = 0.10 level.RejectDo not reject

Answered: Image /qna-images/answer/61d71dae-422d-4a9a-8b6d-8fafae0b68e1.jpg

Answered: minutes. Suppose that a simple random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Consider the data below. Three random samples in different cities were selected. Water use per household per day were measured. Test the claim that the samples come from populations with the same mean. Assume all requirements have been met. Use a 5% level of significance. 1. Identify the tail of the test. [ Select ] 2. Find the P-value. [ Select ] 3. Will the null hypothesis be rejected? [ Select ] 4. Do the populations appear to have the same mean? [ Select ] Sample Data City 1 City 2 City 3 70 66 66 70 64 66 55 45 54 60 41 61 65 58 65 45 44 65 55 46
Samples of airline departure times are obtained and compared to the scheduled departure times. Six major airlines are compared and their mean delay times are recorded. Identify the null and alternative hypotheses for applying an analysis of variance. Choose the correct answer below. OA. Ho: H₁ H₂ H3 H4 H5 H6 H₂: At least two of the means are equal. O B. Ho: At least one of the means is different from the others. Ha: H1 H2 H3 H4 H5=H6 OC. Ho: At least two of the means are equal. Ha: H1 H₂ H3 H4 H5 H6 O D. Ho: H₁ Ha: H1 O E. Ho: H₁ Ha: H1 OF. Ho: H₁ H₂ H3 H4 H5=H6 H₂ H3 H4 H5 H6 H₂ H3 H4 H5 H6 H2 H3 H4 H5=H6 H₂ H3 H4 H5=H6 Ha: At least one of the means is different from the others.
A researcher takes sample temperatures in Fahrenheit of 18 days from Pittsburgh and 16 days from Cleveland. Use the sample data shown in the table. Test the claim that the mean temperature in Pittsburgh greater than the mean temperature in Cleveland. Use a significance level of a = 0.01. Assume the populations are approximately normally distributed with unequal variances. Note that list 1 is longer than list 2, so these are 2 independent samples, not matched pairs. Pittsburgh Cleveland 99 82.1 91.2 60.4 88.1 75.5 91.8 79.5 96 73.3 90.6 57.5 91.5 63.4 69.5 64.1 88.6 78.9 89.2 93 86.2 76.7 83.9 57.5 107.1 58.4 98.5 80.7 82.2 81.4 72.4 55.2 85.2 105.3 The Null Hypotheses is: Ho: µ1 - µ2 = 0 What is the alterative hypothesis? Select the correct symbols for each space. (Note this may view better in full screen mode.) HA: µ1 - µ2 ? v Select an answer Based on these hypotheses, find the following. Round answers to 4 decimal places. Test Statistic = p-value =
Q2. Consider the following table as an example of a possible data set of the people in Bangladesh. Smoking No Yes Total Male 20 40 60 Gender Female 10 30 70 40 Total 30 100 |Conduct appropriate test of hypothesis at 5% level of significance mentioning all necessary formula and steps.
The gas mileage for a 2020 Toyota Prius hybrid vehicle is skewed to the left, with μ = 55 miles per gallon and o = 8 miles per gallon. Suppose a random sample of n = 16 will be selected, the gas mileage will be recorded for each Toyota Prius, and the sample mean will be computed. Based on the information provided, which option applies to the distribution of possible sample mean values? The distribution of all possible sample mean values is normal because the population distribution of responses is normal. The distribution of all possible sample mean values is unknown because the sample size is not large enough and the population distribution of responses is not normal. The distribution of all possible sample mean values is approximately normal because the sample size n is large enough (at least 10 successes and at least 10 failures). The distribution of all possible sample mean values is approximately normal because the sample size n is large enough (larger than 25).
One study claimed that 88 % of college students identify themselves as procrastinators. A professor believes that the claim regarding college students is too high. The professor conducts a simple random sample of 272 college students and finds that 231 of them identify themselves as procrastinators. Does this evidence support the professor's claim that fewer than 88 % of college students are procrastinators? Use a 0.02 level of significance. Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.
One study claimed that 86% of college students identify themselves as procrastinators. A professor believes that the claim regarding college students is too high. The professor conducts a simple random sample of 238 college students and finds that 193 of them identify themselves as procrastinators. Does this evidence support the professor’s claim that fewer than 86% of college students are procrastinators? Use a 0.05 level of significance. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
Q5. The number of points held by a sample of the NHL's highest scorers for both the Eastem Conference and the Westem Conference is shown below. At 0.01 level of significance, (a) can it be concluded that the mean score of Eastem Conference is higher than Westem Conference based on these data? Use P value method. Eastern Conference 83 60 Western Conference 77 59 75 72 68 69 70 58 37 57 78 68 62 55 61 61 59 66
A researcher wants to select a sample from a population with a mean (µ)= 60 and administer a treatment to individuals in the sample. He thinks the treatment will help improve scores. a. State the hypotheses for a one-tailed test. b. For a one-tailed test, would the critical region be located in the positive or right-hand tail of the distribution, or in the negative or left-hand tail of the distribution?
A sociologist claims that the students’ college GPA’s in unrelated to their families’ incomes. For a random sample of 20 students the coefficient of correlation was computed as 0.40. Using the 0.01 significance level, do the formal hypothesis test.Remember to show your steps (including all relevant information) show the steps on how to solve it
A data set includes data from student evaluations of courses. The summary statistics are nequals=8585, x overbarxequals=3.423.42, sequals=0.540.54. Use a 0.010.01 significance level to test the claim that the population of student course evaluations has a mean equal to 3.503.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
A sample of 10 students took a class designed to improve their SAT math scores. Following are their scores before and after the class. Can you conclude that the mean increase in scores is greater than 15 points? Let m1 represent the mean score after the class and md=m1-m2. Use the a=0.05 level and the p-value method with the TI-84 Plus calculator. before is 447,440, 439, 435, 451, 453, 491, 526, 473, 440. after is 482, 479, 451, 431, 454, 463, 511, 529, 493, 466.

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