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Methonol (CHqO,denaity = 361kg/m), aparepponol (C3H8O, density 351KG) ethonol (C2H60, donaity= 35,9 Kglm?), Butonol (CAH,0O deneity= 380 Ikglm?) 3. %3D 3.374 mL of ethonol aue in a sompe. Detemine the numler ok stoms of Hydnogen in this aount of alcohol

Methonol (CHqO,denaity = 361kg/m), aparepponol (C3H8O, density 351KG) ethonol (C2H60, donaity= 35,9 Kglm?), Butonol (CAH,0O deneity= 380 Ikglm?) 3. %3D 3.374 mL of ethonol aue in a sompe. Detemine the numler ok stoms of Hydnogen in this aount of alcohol

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Methonor CCHqO, density = 361kg/m), prepponol CC3H8O, density =351KG) ethond (C2H60, donsety= 35,9 kglm) Butonol (CaH,oO density: 380 cglm?) m3 3.374ML f ethonol aue in a stoms of Hydnogen in this amerint of alcóhol sompe. Determine the numler of
Transcribed Image Text:Methonor CCHqO, density = 361kg/m), prepponol CC3H8O, density =351KG) ethond (C2H60, donsety= 35,9 kglm) Butonol (CaH,oO density: 380 cglm?) m3 3.374ML f ethonol aue in a stoms of Hydnogen in this amerint of alcóhol sompe. Determine the numler of
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Step 1

Given : Volume of ethanol i.e C2H6O = 3.374 mL

And density of C2H6O = 359 Kg/m3 = 0.359 g/mL                                        (since 1 Kg/m3 = 1000 g/mL)

 

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