Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:9) How many grams of KNO3 are required to make 100.0 mL of a 0.531 M KNO3 solution? (Answer:
5.37 g KNO3)
Volume of soIution (V) = 100.0OML= 0.100L
Unifs of mojanty= mol /L
%3D
Molanty of soluhon(M)=0.531H= 0.531 mol/L
Nu -W
n= moles of soIule = mass/molar mass Molar mass of KNO3= 101.1 glmol
Mass of KN03=
V = Volume oF SOluion in litres
H= (mass/ molar mass) (1/v)
Mass = M molar mass V
Mass-o. 531 mol/L 101. 1g/mol 0. 100 L
M= (mass/molar mass) × (1/V)
Mass = 5.37D.
10) How many milliliters of the solution prepared in the question above would be required to make
250.0 mL of a 0.1000 M KNO3 solution? (Answer: 47.1 mL)
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