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Calculate the volume in liters of a 0.091M sodium nitrate solution that contains 11.0 mol of sodium nitrate (NaNO,). Be sure your answer has the correct number of significant digits. 0t 0.8 X 5

Calculate the volume in liters of a 0.091M sodium nitrate solution that contains 11.0 mol of sodium nitrate (NaNO,). Be sure your answer has the correct number of significant digits. 0t 0.8 X 5

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Problem Statement:** Calculate the volume in liters of a 0.0914 M sodium nitrate solution that contains 1.10 mol of sodium nitrate (NaNO₃). Be sure your answer has the correct number of significant digits. **Input Fields:** - A text box for numerical input labeled with a molarity and volume equation icon. - A checkmark and cancel button to submit or clear the entry. **Solution Explanation:** To find the volume of the solution, use the formula: \[ C = \frac{n}{V} \] Where: - \( C \) = concentration (molarity) in mol/L - \( n \) = amount of solute in moles - \( V \) = volume of solution in liters Rearrange to solve for \( V \): \[ V = \frac{n}{C} \] Substitute the given values: \[ V = \frac{1.10\ \text{mol}}{0.0914\ \text{M}} \] Calculate the volume ensuring the correct number of significant digits.
Transcribed Image Text:**Problem Statement:** Calculate the volume in liters of a 0.0914 M sodium nitrate solution that contains 1.10 mol of sodium nitrate (NaNO₃). Be sure your answer has the correct number of significant digits. **Input Fields:** - A text box for numerical input labeled with a molarity and volume equation icon. - A checkmark and cancel button to submit or clear the entry. **Solution Explanation:** To find the volume of the solution, use the formula: \[ C = \frac{n}{V} \] Where: - \( C \) = concentration (molarity) in mol/L - \( n \) = amount of solute in moles - \( V \) = volume of solution in liters Rearrange to solve for \( V \): \[ V = \frac{n}{C} \] Substitute the given values: \[ V = \frac{1.10\ \text{mol}}{0.0914\ \text{M}} \] Calculate the volume ensuring the correct number of significant digits.
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