Question 2Thermochemistry2.1 Methanol is an attractive fuel source in a sustainable, green economy. The chemical energy inherent inmethanol can be utilized in a multitude of reactions. Consider the following reaction for thedecomposition of methanol:CH3OH(f) → CH,(g)+ /½02(g)Use Hess' Law to calculate the enthalpy change (in kJ-mol-') of this reaction, given the following knownthermochemical data:02(g) + 2H2(g) → 2H20(£)CH,(g) + H20(g)→ 3H2(g) + CO(g)H20(g) → H20(e)2H2(g) + CO(g) → CH3OH(f)AH, = -571.6 k] •mol-1AH, = 206.1 k] • mol-1AH, = -44.00 k] • mol-1AH,= -128.3 k] • mol-1 2.2 Methanol can also be combusted in the presence of oxygen in order to release its energy. 5.24 g of methanolwas placed in a bomb calorimeter (with a known heat capacity of 2.53 kJ-K'), together with 3.25 kg waterwith an initial temperature of 65.0 °C. After methanol is combusted, what will the temperature of the waterbe, given that the standard enthalpy of combustion of methanol is AH=-715.0 kJ-mol-1?

2.1) According to Hess Law of constant heat summation,"enthalpy change will be same whether the…

Methanol is an attractive fuel source in a sustainable, green economy. The chemical energy inherent in methanol can be utilized in a multitude of reactions. Consider the following reaction for the decomposition of methanol: 2.1 CH3OH(e) → CH4(g) + 1½02(g) Use Hess' Law to calculate the enthalpy change (in kJ-mol') of this reaction, given the following known thermochemical data: 02(g) + 2H2(g) → 2H20(£) CH,(g) + H20(g) → 3H2(g) + CO(g) H20(g) → H20(e) 2H2(g) + CO(g) → CH3OH(?) AH, = -571.6 k] • mol- AH, = 206.1 k] · mol-1 AH, = -44.00 k] • mol-1 AH, = -128.3 k] • mol-1 %3!

Methanol is an attractive fuel source in a sustainable, green economy. The chemical energy inherent in methanol can be utilized in a multitude of reactions. Consider the following reaction for the decomposition of methanol: 2.1 CH3OH(e) → CH4(g) + 1½02(g) Use Hess' Law to calculate the enthalpy change (in kJ-mol') of this reaction, given the following known thermochemical data: 02(g) + 2H2(g) → 2H20(£) CH,(g) + H20(g) → 3H2(g) + CO(g) H20(g) → H20(e) 2H2(g) + CO(g) → CH3OH(?) AH, = -571.6 k] • mol- AH, = 206.1 k] · mol-1 AH, = -44.00 k] • mol-1 AH, = -128.3 k] • mol-1 %3!

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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