Methane and water react to form carbon monoxide and hydrogen, like this: CH (9)+H,O(9)→ CO(g)+3H,(g) Use this chemical equation to answer the questions in the table below. Suppose 105. mmol of CH, and O None. 105. mmol of H,0 are added to an O Some, but less than 105. mmol. O 105. mmol. empty flask. How much CO will be in the flask at equilibrium? O More than 105. mmol. O None. Suppose 115. mmol of CO and 345. mmol of H, are added to an O Some, but less than 115. mmol. empty flask. How much CO will be in the flask at equilibrium? O 115. mmol. O More than 115. mmol.
Methane and water react to form carbon monoxide and hydrogen, like this: CH (9)+H,O(9)→ CO(g)+3H,(g) Use this chemical equation to answer the questions in the table below. Suppose 105. mmol of CH, and O None. 105. mmol of H,0 are added to an O Some, but less than 105. mmol. O 105. mmol. empty flask. How much CO will be in the flask at equilibrium? O More than 105. mmol. O None. Suppose 115. mmol of CO and 345. mmol of H, are added to an O Some, but less than 115. mmol. empty flask. How much CO will be in the flask at equilibrium? O 115. mmol. O More than 115. mmol.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Methane and water react to form carbon monoxide and hydrogen, like this:
CH,(9)+H,O(9)
- CO(g)+3H,(g)
Use this chemical equation to answer the questions in the table below.
Suppose 105. mmol of CH and
O None.
105. mmol of H,0 are added to an
O Some, but less than 105. mmol.
O 105. mmol.
empty flask. How much CO will be
in the flask at equilibrium?
O More than 105. mmol.
Suppose 115. mmol of CO and
O None.
345. mmol of H, are added to an
O Some, but less than 115. mmol.
empty flask. How much C0 will be
in the flask at equilibrium?
O 115. mmol.
O More than 115. mmol.
Explanation
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