Melissa was trying to synthesize a homopolymer of poly(8-decalactone), however she didn't have any 1,4-benzenedimethanol so she decided to use benzyl alcohol as her initiator instead. How is this going to affect her final polymer? Will she still be able to form a triblock copolymer? O The initiator is not important, it is only there to get the reaction started. Thus, her final polymer will be unaffected. She will be able to form a triblock copolymer. O Her final polymer will have a significantly lower molecular weight than expected because the benzyl alcohol has a lower molecular weight than the 1,4-bezenedimethanol. She will still form a triblock copolymer. O It will not affect her final polymer if she uses half of the amount of the monomer since there is only one alcohol group for it to interact with. She will be able to form a triblock copolymer. O The polymer will only grow from one side of the initiator. She will not be able to form a triblock copolymer, she will form a diblock instead.
Melissa was trying to synthesize a homopolymer of poly(8-decalactone), however she didn't have any 1,4-benzenedimethanol so she decided to use benzyl alcohol as her initiator instead. How is this going to affect her final polymer? Will she still be able to form a triblock copolymer? O The initiator is not important, it is only there to get the reaction started. Thus, her final polymer will be unaffected. She will be able to form a triblock copolymer. O Her final polymer will have a significantly lower molecular weight than expected because the benzyl alcohol has a lower molecular weight than the 1,4-bezenedimethanol. She will still form a triblock copolymer. O It will not affect her final polymer if she uses half of the amount of the monomer since there is only one alcohol group for it to interact with. She will be able to form a triblock copolymer. O The polymer will only grow from one side of the initiator. She will not be able to form a triblock copolymer, she will form a diblock instead.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Melissa was trying to synthesize a homopolymer of poly(8-decalactone), however she didn't have
any 1,4-benzenedimethanol so she decided to use benzyl alcohol as her initiator instead. How is this
going to affect her final polymer? Will she still be able to form a triblock copolymer?
O The initiator is not important, it is only there to get the reaction started. Thus, her final polymer will be
unaffected. She will be able to form a triblock copolymer.
O Her final polymer will have a significantly lower molecular weight than expected because the benzyl alcohol
has a lower molecular weight than the 1,4-bezenedimethanol. She will still form a triblock copolymer.
O It will not affect her final polymer if she uses half of the amount of the monomer since there is only one
alcohol group for it to interact with. She will be able to form a triblock copolymer.
O The polymer will only grow from one side of the initiator. She will not be able to form a triblock copolymer,
she will form a diblock instead.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe3e6467c-c9fe-4caa-a94a-89b03f6b310d%2F76f4dded-1c99-4887-a31e-6ed1d30e5f36%2Fedeeuj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Melissa was trying to synthesize a homopolymer of poly(8-decalactone), however she didn't have
any 1,4-benzenedimethanol so she decided to use benzyl alcohol as her initiator instead. How is this
going to affect her final polymer? Will she still be able to form a triblock copolymer?
O The initiator is not important, it is only there to get the reaction started. Thus, her final polymer will be
unaffected. She will be able to form a triblock copolymer.
O Her final polymer will have a significantly lower molecular weight than expected because the benzyl alcohol
has a lower molecular weight than the 1,4-bezenedimethanol. She will still form a triblock copolymer.
O It will not affect her final polymer if she uses half of the amount of the monomer since there is only one
alcohol group for it to interact with. She will be able to form a triblock copolymer.
O The polymer will only grow from one side of the initiator. She will not be able to form a triblock copolymer,
she will form a diblock instead.
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