#8 For a compound containing 181.351 g C, 36.5115 ga) the empirical formulaC2H4NC3H7NC3H6N3b) theC6H6N3C6H14N2C6H14N3C6H21N3C12H28N4c) theC15H36N5sition of H in the compour12.38%14.68%62.88%none of these Celsius:To Fahrenheit[°F] = ([°C] x 1.8) + 32To Kelvin[K] = [°C] + 273.15Kelvin to Celsius['C] = [K] – 273.15For a compound containing 181.351 g C, 36.5115 g H, and 70.8906 g N, with a molar mass between 160.0 and 180.0 g/mol, determinea) the empirical formulab) the molecular formulac) the mass percent composition of H in the compound.

Answered: Image /qna-images/answer/0e23f1e3-2782-4beb-a70b-bede8ec790d8.jpg

For a compound containing 181.351 g C, 36.5115 g a) the empirical formula C2H4N C3H7N C3H6N3 b) the C6H6N3 C6H14N2 C6H14N3 C6H21N3 C12H28N4 c) the C15H36N5 sition of H in the compour 12.38% 14.68% 62.88% none of these

For a compound containing 181.351 g C, 36.5115 g a) the empirical formula C2H4N C3H7N C3H6N3 b) the C6H6N3 C6H14N2 C6H14N3 C6H21N3 C12H28N4 c) the C15H36N5 sition of H in the compour 12.38% 14.68% 62.88% none of these

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

For a compound containing 181.351 g C, 36.5115 g
a) the empirical formula
C2H4N
C3H7N
C3H6N3
b) the
C6H6N3
C6H14N2
C6H14N3
C6H21N3
C12H28N4
c) the
C15H36N5
sition of H in the compour
12.38%
14.68%
62.88%
none of these

Celsius:
To Fahrenheit
[°F] = ([°C] x 1.8) + 32
To Kelvin
[K] = [°C] + 273.15
Kelvin to Celsius
['C] = [K] – 273.15
For a compound containing 181.351 g C, 36.5115 g H, and 70.8906 g N, with a molar mass between 160.0 and 180.0 g/mol, determine
a) the empirical formula
b) the molecular formula
c) the mass percent composition of H in the compound.

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