ANotificationsMedical research has shown that repeated wrist extensions beyond 20 degrees increase the risk of wrist and hand injuries. Each of 24 students at a university used a proposed new computer mouse design, and while using the mouse, each student's wrist extension was recorded. Dataconsistent with summary values given in a paper are given here.26 27 25 25 27 25 25 24 24 24 25 2822 25 24 28 27 26 31 25 28USE SALT(a) Use these data27 27 25thoughts @totsofmayn - 28meacted withestimate the mean wrist extension for people using this new mouse design using a 90% confidence interval. (Round your answers to three decimal places.)AllationsMath: Statistics po ang topic

Give data is26,27,25,25,27,25,25,24,24,24,25,28,22,25,24,28,27,26,31,25,28,27,27,25sample…

Answered: Medical research has shown that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A graduate student is interested in how viewing different types of scenes affects working memory. For his study, he selects a random sample of 36 adults. The subjects complete a series of working memory tests before and after walking in an urban setting. Before the walk, the mean score on the test of working memory was 9.1. After the walk, the mean score was 1.4 higher. The graduate student has no presupposed assumptions about how viewing different types of scenes affects working memory, so he formulates the null and alternative hypotheses as: H00 : μDD = 0 H11 : μDD ≠ 0 Assume that the data satisfy all of the required assumptions for a repeated-measures t test. The graduate student calculates the following statistics for his hypothesis test: Mean difference (MDD) 1.4 Estimated population standard deviation of the differences (s) 1.6 Estimated standard error of the mean differences (sMDMD) 0.2667 Degrees of freedom (df) 35 The t statistic 5.25 The critical values of t…
Do E) i ii & iii please
A school principal claims that the number of students who are tardy to school does not vary from month to month. A survey over the school year produced the following results. Using a 0.01 level of significance, test a teacher's claim that the number of tardy students does vary by the month. Number Aug. Oct. Sept. 18 13 19 Tardy Students Nov. Dec. Jan. 14 8 Feb. Mar. Apr. 6 13 11 15 May 16 Copy Data Step 2 of 4: Calculate the expected value for the number of tardies in October. Enter your answer as a fraction or a decimal rounded to three decimal places.
A school principal claims that the number of students who are tardy to school does not vary from month to month. A survey over the school year produced the following results. Using a 0.01 level of significance, test a teacher's claim that the number of tardy students does vary by the month. Number Aug. Sept. Oct. 18 13 19 Tardy Students Nov. 14 Dec. Jan. Feb. Mar. Apr. May 8 6 13 11 15 16 Copy Data Step 3 of 4: Compute the value of the test statistic. Round any intermediate calculations to at least six decimal places, and round your final answer to three decimal places.
5. Dust mite allergies. Refer to Exercises 4.2 (p. 138) and 4.13 (p. 143). Each home with a dust mite level that ex- ceeds 2µg/g will spend $2,000 for an allergen air purifica- tion system. Find the mean and variance of the total amount spent by the four sampled homes. Give a range where this total is likely to fall.
An experiment was conducted to determine if exposure to an advertisement would change attitude toward a product. Each subject’s attitude before and after exposure to the advertisement was recorded, using a valid ten point scale. The results indicated: Subject Attitude Post Exposure Attitude Pre Exposure 1 6 4 2 8 5 3 6 6 4 4 3 5 7 2 6 6 3 7 9 6 8 7 6 9 8 5 10 8 6 Set up hypotheses and test to determine if the mean attitude toward the product increased as a result of exposure to the advertisement. (Note: these samples must be regarded as dependent, as each subject served as both a control (pre-exposure) and a treatment (post exposure). Fully interpret your result.
On a recent evening, a police crackdown on prostitution solicitation resulted in 19 arrests. The ages of the persons arrested were 4.9 17 18 24 37 32 49 61 20 21 21 25 24 24 26 30 33 35 22 19 a. Calculate an appropriate measure of central tendency. b. Explain why this measure of central tendency best represents typi- cality for these data.
I need help making a relative frequency histogram from this data.
number 28 The following data shows the price of a certain stock over the last 8 months. Month Price 1 2.10 2 1.98 3 2.01 4 1.89 5 1.90 6 1.89 7 1.72 8 1.65 (a) Develop a scatter diagram and draw a trend line through the points. A graph has a horizontal axis labeled "Month" with values from 0 to 10 and a vertical axis labeled "Price" with values from 0 to 2.5. The scatter diagram has 8 points. A line goes through the center of the pattern of points. A pattern goes down and right becoming more steep from (1, 1.7) to (8, 1.25). A graph has a horizontal axis labeled "Month" with values from 0 to 10 and a vertical axis labeled "Price" with values from 0 to 2.5. The scatter diagram has 8 points. A line goes through the center of the pattern of points. A pattern goes down and right from (1, 2.1) to (8, 1.65). A graph has a horizontal axis labeled "Month" with values from 0 to 10 and a vertical axis labeled "Price" with values from 0 to 2.5. The scatter…
5.28 Risks and insurance. The idea of insurance is that we all face risks that are unlikely but carry high cost. Think of a fire destroying your home. So we form a group to share the risk: we all pay a small amount, and the insurance policy pays a large amount to those few of us whose homes burn down. An insurance company looks at the records for millions of homeowners and sees that the mean loss from fire in a year is μ = $250 per house and that the standard deviation of the loss is σ = $1000. (The distribution of losses is extremely right-skewed: most people have $0 loss, but a few have large losses.) The company plans to sell fire insurance for $250 plus enough to cover its costs and profit. If the company sells 25,000 policies, what is the approximate probability that the average loss in a year will be greater than $270?
A study from 2014 found that adults in the US spend an average of 11 hours per day watching, reading, listening to or simply interacting with media. Researchers at UCLA suspect students spend less time engaging media. They grouped UCLA students by class section, randomly selected 20 class sections, and administered a survey to each student in those randomly selected class sections. The following data represents the mean time (in hours) per day spent engaging media for each of the randomly selected classes: 9.5 11.5 6.0 7.5 8 9.5 10.5 11 12 8.2 5 9.5 8.2 9.3 10.8 11 13 8.6 9.5 10.5 What would be the 99% Confidence Interval for mean time (in hours) spent per day engaging media for UCLA students. Do this "by hand", using appripriate symbols/formulas/tables.
Please answer part d), e) and f)

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