Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimedthat the mean of this population is 6.75 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 19 collegestudents and record the number of hours each slept the night before finals.Follow the steps below to construct a 99% confidence interval for the population mean of all the numbers of hours slept by college students the night beforefinals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.)(a) Click on "Take Sample" to see the results for your random sample.Number of studentsSample meanSample standarddeviationTake Sample196.5041.421Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 99%confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute".Sample size:Standard error:Point estimate:Critical valuesSample standard deviation:Margin of error:0.00s -2.8780.010-2.552Critical value:0.025 -2.10199% confidence interval:f0.050-1.734ExplanationCheck02021 McGraw Hill Education. All Rights Reserved Terms of UsePrivacy AccessibiltyMacBook Airesc**888 .%23$&**3457.8.9.QRYUPFHJKCValtaltioncommandcommandoptiocV - -- -Constructing a confidence interval to test a claim about the..(b) Baseu on your sample, graph the 99% confidence interval for the population mean of all the numbers of hours slept by college students the night beforefinals.• Enter the values for the lower and upper limits on the graph to show your confidence interval.• For the point (), enter the claim 6.75 from the report.99% confidence interval:0.00010.0005.0000.0002.0004.0006.0008.00010.000(c) Does the 99% confidence interval you constructed contradict the claim made in the report?Choose the best answer from the choices below.O No, the confidence interval does not contradict the claim. The mean of 6.75 hours from the report is inside the 99%confidence interval.O No, the confidence interval does not contradict the claim. The mean of 6.75 hours from the report is outside the 99%confidence interval.O Yes, the confidence interval contradicts the claim. The mean of 6.75 hours from the report is inside the 99% confidenceinterval.O Yes, the confidence interval contradicts the claim. The mean of 6.75 hours from the reportconfidence interval.outside the 99%ExplanationCheck62021 McGraw HI Education. All Rights Reserved Terms of UseI PrivacyI AccessibilityMacBook Airesc888 aF7%232$&*5689WERTYUPFJ KCMaltcommandcommandoptB.

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Description: Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimedthat the mean of this population is 6.75 hours. As a student wellness advocate, you want

The formula to compute confidence interval is, x±t(α/2,df)*sn The formula to compute margin of error…

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mean of this population is 6.75 hours. As a student wellness advocate, you and record the number of hours each slept the night before finals. e steps below to construct a 99% confidence interval for the population me en state whether the confidence interval you construct contradicts the repo ick on "Take Sample" to see the results for your random sample.

mean of this population is 6.75 hours. As a student wellness advocate, you and record the number of hours each slept the night before finals. e steps below to construct a 99% confidence interval for the population me en state whether the confidence interval you construct contradicts the repo ick on "Take Sample" to see the results for your random sample.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

100%

Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed
that the mean of this population is 6.75 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 19 college
students and record the number of hours each slept the night before finals.
Follow the steps below to construct a 99% confidence interval for the population mean of all the numbers of hours slept by college students the night before
finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.)
(a) Click on "Take Sample" to see the results for your random sample.
Number of students
Sample mean
Sample standard
deviation
Take Sample
19
6.504
1.421
Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 99%
confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute".
Sample size:
Standard error:
Point estimate:
Critical values
Sample standard deviation:
Margin of error:
0.00s -2.878
0.010-2.552
Critical value:
0.025 -2.101
99% confidence interval:
f0.050-1.734
Explanation
Check
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Constructing a confidence interval to test a claim about the..
(b) Baseu on your sample, graph the 99% confidence interval for the population mean of all the numbers of hours slept by college students the night before
finals.
• Enter the values for the lower and upper limits on the graph to show your confidence interval.
• For the point (), enter the claim 6.75 from the report.
99% confidence interval:
0.000
10.000
5.000
0.000
2.000
4.000
6.000
8.000
10.000
(c) Does the 99% confidence interval you constructed contradict the claim made in the report?
Choose the best answer from the choices below.
O No, the confidence interval does not contradict the claim. The mean of 6.75 hours from the report is inside the 99%
confidence interval.
O No, the confidence interval does not contradict the claim. The mean of 6.75 hours from the report is outside the 99%
confidence interval.
O Yes, the confidence interval contradicts the claim. The mean of 6.75 hours from the report is inside the 99% confidence
interval.
O Yes, the confidence interval contradicts the claim. The mean of 6.75 hours from the report
confidence interval.
outside the 99%
Explanation
Check
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