Decide whether it describes a confidence interval for a proportion or a confidence interval for a mean. Apply the correct formula to calculate the confidence interval in the format of an estimate ± margin of error. During the 2016 season, Mark Williams played in 18 golf matches and used his driver club 126 times, hitting his drives an average of 278 yards per drive, with a standard deviation of 15 yards per drive. Calculate a 95% confidence interval for the distance he was able to hit his driver club in that season.

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**Confidence Intervals: Understanding and Calculation**

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**Instructions:**
1. For each problem below, decide whether it describes a confidence interval for a proportion or a confidence interval for a mean.
2. Apply the correct formula to calculate the confidence interval in the format of an estimate ± margin of error.

---

**Example Problem:**
During the 2016 season, Mark Williams played in 18 golf matches and used his driver club 126 times, hitting his drives an average of 278 yards per drive, with a standard deviation of 15 yards per drive. Calculate a 95% confidence interval for the distance he was able to hit his driver club in that season.

---

**Explanation:**
In the problem provided, we need to determine and calculate the confidence interval for the mean distance Mark Williams hit his driver club, using the given data. 

1. **Identify the type of confidence interval:** This is a confidence interval for a mean because we are looking to estimate the average distance (a continuous variable) with a given standard deviation.

2. **Formulate the confidence interval:** The confidence interval for the mean is usually calculated using the formula:

   \[
   \text{Confidence Interval} = \bar{x} \pm Z \left(\frac{\sigma}{\sqrt{n}}\right)
   \]
   Where:
   - \(\bar{x}\) is the sample mean.
   - \(Z\) is the Z-score corresponding to the desired confidence level.
   - \(\sigma\) is the standard deviation.
   - \(n\) is the sample size.

3. **Plug in the values:**
   \[
   \bar{x} = 278 \text{ yards per drive}
   \]
   \[
   \sigma = 15 \text{ yards}
   \]
   \[
   n = 126 \text{ drives}
   \]
   For a 95% confidence level, the Z-score (\(Z\)) is approximately 1.96.

4. **Calculate the margin of error:**
   \[
   \text{Margin of Error} = 1.96 \left(\frac{15}{\sqrt{126}}\right)
   \]
   \[
   \text{Margin of Error} \approx 1.96 \left(\frac{15}{11.225}\right)
   \]
   \[
   \text{Margin of Error} \approx
Transcribed Image Text:**Confidence Intervals: Understanding and Calculation** --- **Instructions:** 1. For each problem below, decide whether it describes a confidence interval for a proportion or a confidence interval for a mean. 2. Apply the correct formula to calculate the confidence interval in the format of an estimate ± margin of error. --- **Example Problem:** During the 2016 season, Mark Williams played in 18 golf matches and used his driver club 126 times, hitting his drives an average of 278 yards per drive, with a standard deviation of 15 yards per drive. Calculate a 95% confidence interval for the distance he was able to hit his driver club in that season. --- **Explanation:** In the problem provided, we need to determine and calculate the confidence interval for the mean distance Mark Williams hit his driver club, using the given data. 1. **Identify the type of confidence interval:** This is a confidence interval for a mean because we are looking to estimate the average distance (a continuous variable) with a given standard deviation. 2. **Formulate the confidence interval:** The confidence interval for the mean is usually calculated using the formula: \[ \text{Confidence Interval} = \bar{x} \pm Z \left(\frac{\sigma}{\sqrt{n}}\right) \] Where: - \(\bar{x}\) is the sample mean. - \(Z\) is the Z-score corresponding to the desired confidence level. - \(\sigma\) is the standard deviation. - \(n\) is the sample size. 3. **Plug in the values:** \[ \bar{x} = 278 \text{ yards per drive} \] \[ \sigma = 15 \text{ yards} \] \[ n = 126 \text{ drives} \] For a 95% confidence level, the Z-score (\(Z\)) is approximately 1.96. 4. **Calculate the margin of error:** \[ \text{Margin of Error} = 1.96 \left(\frac{15}{\sqrt{126}}\right) \] \[ \text{Margin of Error} \approx 1.96 \left(\frac{15}{11.225}\right) \] \[ \text{Margin of Error} \approx
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