(McQuarrie 4-22) Show that the following functions are orthonormal over the interval -x < x < ∞. These functions are the lowest eigenfunctions of the harmonic oscillator problem, which we will study in Chapter 5.) πT 1/4 40(x) = e-x²/2 4 1/4 41(x) = -x²/2 xe πT 42(x) = (+17) 14 (2x² - 1)e-²²/2 Hint: See the Table of Integrals handout for tips on integrating these even and odd functions. (McQuarrie 4-26) Prove that if 8nm is the Kronecker delta, then, 1 n = m бит = 0 nm Σιδη = Cm and Σanbmdnm = Σ ambn n=1 n=1 m=1 n These results will be used in various derivations. Hint: If you find this confusing, pick some particular value for m (e.g. m = 2) and then expand out the sums. Then see what the Kronecker delta does to each term in the sum.

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Chapter1: Chemical Foundations
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(McQuarrie 4-22) Show that the following functions are orthonormal over the interval
-x < x < ∞. These functions are the lowest eigenfunctions of the harmonic oscillator
problem, which we will study in Chapter 5.)
πT
1/4
40(x) =
e-x²/2
4 1/4
41(x) =
-x²/2
xe
πT
42(x) =
(+17) 14 (2x² - 1)e-²²/2
Hint: See the Table of Integrals handout for tips on integrating these even and odd functions.
(McQuarrie 4-26) Prove that if 8nm is the Kronecker delta,
then,
1
n = m
бит
=
0 nm
Σιδη
= Cm
and
Σanbmdnm = Σ ambn
n=1
n=1 m=1
n
These results will be used in various derivations.
Hint: If you find this confusing, pick some particular value for m (e.g. m = 2) and then
expand out the sums. Then see what the Kronecker delta does to each term in the sum.
Transcribed Image Text:(McQuarrie 4-22) Show that the following functions are orthonormal over the interval -x < x < ∞. These functions are the lowest eigenfunctions of the harmonic oscillator problem, which we will study in Chapter 5.) πT 1/4 40(x) = e-x²/2 4 1/4 41(x) = -x²/2 xe πT 42(x) = (+17) 14 (2x² - 1)e-²²/2 Hint: See the Table of Integrals handout for tips on integrating these even and odd functions. (McQuarrie 4-26) Prove that if 8nm is the Kronecker delta, then, 1 n = m бит = 0 nm Σιδη = Cm and Σanbmdnm = Σ ambn n=1 n=1 m=1 n These results will be used in various derivations. Hint: If you find this confusing, pick some particular value for m (e.g. m = 2) and then expand out the sums. Then see what the Kronecker delta does to each term in the sum.
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