Material Aluminium Mass at each end (g) 0 100 200 300 400 500 Material Brass Mass at each end (g) 0 100 200 300 400 500 Table 8 Results for circular bending – aluminium beam 1 E (Nmm¹²) Width b (mm) Depth d (mm) 19.91 3.2 6.9 x 10 Deflection (mm) 0 0.60 1.16 1.72 2.24 2.84 Deflection (mm) Applied moment M 0 0.33 0.70 1.07 1.46 1.81 (Nm) 0 0.588 1.176 1.764 2.352 2.940 Applied moment M Radius of curvature R (m) Table 9 Results for circular bending - brass beam 2 E (Nmm²) Width b (mm) Depth d (mm) 1.05 x 10° 19.91 3.2 (Nm) 0 0.588 1.176 1.764 2.352 2.940 33.3 17.2 11.6 9.09 7.04 Radius of curvature R (m) - 1/R 60.6 28.6 18.7 13.6 11.1 0.0299 0.0581 0.0862 0.1100 0.1420 1/R 0.0165 0.0350 0.0534 0.0730 0.0900 I (mm²) 54.5 M/I 0 I (mm²) 54.5 M/I 0

Material Aluminium Mass at each end (g) 0 100 200 300 400 500 Material Brass Mass at each end (g) 0 100 200 300 400 500 Table 8 Results for circular bending – aluminium beam 1 E (Nmm¹²) Width b (mm) Depth d (mm) 19.91 3.2 6.9 x 10 Deflection (mm) 0 0.60 1.16 1.72 2.24 2.84 Deflection (mm) Applied moment M 0 0.33 0.70 1.07 1.46 1.81 (Nm) 0 0.588 1.176 1.764 2.352 2.940 Applied moment M Radius of curvature R (m) Table 9 Results for circular bending - brass beam 2 E (Nmm²) Width b (mm) Depth d (mm) 1.05 x 10° 19.91 3.2 (Nm) 0 0.588 1.176 1.764 2.352 2.940 33.3 17.2 11.6 9.09 7.04 Radius of curvature R (m) - 1/R 60.6 28.6 18.7 13.6 11.1 0.0299 0.0581 0.0862 0.1100 0.1420 1/R 0.0165 0.0350 0.0534 0.0730 0.0900 I (mm²) 54.5 M/I 0 I (mm²) 54.5 M/I 0

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)

5th Edition

ISBN:9781305084766

Author:Saeed Moaveni

Publisher:Saeed Moaveni

Chapter12: Electric Current And Related Variables In Engineering

Section12.2: Electrical Circuits And Components

Problem 6BYG

See similar textbooks

Similar questions

using Figure 5-27, what is the advantage of the suspended type magnet over the other two types of magnets?
Direction: Circle T to indicate true statements or F to indicate false statements. Copper is not a conductor of electricity because only materials that are magnetic can conduct electricity.
A tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.
A tensile test was performed on a metal specimen with a diameter of 1 2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The dam were plotted on a load-displacement graph. P vs. L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P/L =1392 kips/in. What is the modulus of elasticity?
The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
According to Figure 5-20, is ii possible to completely separate one of the four materials from the other three? Explain your answer.
A beam is part of the framing system for the floor of an office building. The floor is subjected to both dead loads and live loads. The maximum moment caused by the service dead load is 45 ft-kips, and the maximum moment for the service live load is 63 ft-kips (these moments occur at the same location on the beam and can therefore be combined). a. If load and resistance factor design is used, determine the maximum factored bending moment (required moment strength). What is the controlling AISC load combination? b. What is the required nominal moment strength for a resistance factor of 0.90? c. If allowable strength design is used, determine the required moment strength. What is the controlling AISC lead combination? d. What is the required nominal moment strength for a safety factor of 1.67?
Compute the nominal shear strength of an M107.5 of A572 Grad 65 steel.
Two materials, A and B, are to be separated using two unit operations, 1 and 2. The feed has 10 tons/h A and 4 tons/h B. The split (fraction of material rejected by each operation) is given in Table P5-14. a. Which sequence of operations, (l?2) or (2?1), will yield the greatest recovery of material A? b. What will be the purity of material A using that sequence? c. What will be the efficiency of separation for the entire process train with regard to material A using the Worrell-Stesed equation?
The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.
Solve Problem 15 .17 for the loading shown in Fig. P15.17 and a settlement of 50 mm at support D. FIG. P15.17, P15.21
A tensile test was performed on a metal specimen having a circular cross section with a diameter of 1 2 inch. The gage length (the length over which the elongation is measured) is 2 inches. For a load 13.5 kips, the elongation was 4.6610 3 inches. If the load is assumed to be within the linear elastic rang: of the material, determine the modulus of elasticity.