Match the peak chromatogram and the possible compound based on the information given (example: Peak A – Compound A). All peaks originated from one HPLC injection. 0.14 Peak 1 Peak 2 0.12 Peak 3 0.10- 1564 0.08 1730 1345 Peak 4 0.06- Peak A 0.04 1311 Peak B 1211 0.02- 567 0.00- 1.00 4.50 250 min 0.00 0.50 1.50 200 300 3.50 4.00 5.00 a) Mode: Normal phase HPLC Peaks: 1, 2, 3 and 4 Compounds mix: Aspartame; Benzoic Acid; Caffeine; Sorbic Acid NH 2 ОН HO, HO, Benzoic acid Caffeine Sorbic Acid Aspartame

Match the peak chromatogram and the possible compound based on the information given (example: Peak A – Compound A). All peaks originated from one HPLC injection. 0.14 Peak 1 Peak 2 0.12 Peak 3 0.10- 1564 0.08 1730 1345 Peak 4 0.06- Peak A 0.04 1311 Peak B 1211 0.02- 567 0.00- 1.00 4.50 250 min 0.00 0.50 1.50 200 300 3.50 4.00 5.00 a) Mode: Normal phase HPLC Peaks: 1, 2, 3 and 4 Compounds mix: Aspartame; Benzoic Acid; Caffeine; Sorbic Acid NH 2 ОН HO, HO, Benzoic acid Caffeine Sorbic Acid Aspartame

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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2. The reagent blank reading for a method to detect glucose gave the following fluorescence readings: 200, 215, 230, 222, and 212 RFU. Considering the calibration curve shown below, what is the limit of detection and limit of quantitation for this method? 6000 4000 2000 ¥=51 993x 119 63 50 100 Glucose ipmol) RFU (Ex/Em =535/587)
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