Match the peak chromatogram and the possible compound based on the information given (example: Peak A – Compound A). All peaks originated from one HPLC injection. 0.14 Peak 1 Peak 2 0.12 Peak 3 0.10- 1564 0.08 1730 1345 Peak 4 0.06- Peak A 0.04 1311 Peak B 1211 0.02- 567 0.00- 1.00 4.50 250 min 0.00 0.50 1.50 200 300 3.50 4.00 5.00 a) Mode: Normal phase HPLC Peaks: 1, 2, 3 and 4 Compounds mix: Aspartame; Benzoic Acid; Caffeine; Sorbic Acid NH 2 ОН HO, HO, Benzoic acid Caffeine Sorbic Acid Aspartame

Match the peak chromatogram and the possible compound based on the information given (example: Peak A – Compound A). All peaks originated from one HPLC injection. 0.14 Peak 1 Peak 2 0.12 Peak 3 0.10- 1564 0.08 1730 1345 Peak 4 0.06- Peak A 0.04 1311 Peak B 1211 0.02- 567 0.00- 1.00 4.50 250 min 0.00 0.50 1.50 200 300 3.50 4.00 5.00 a) Mode: Normal phase HPLC Peaks: 1, 2, 3 and 4 Compounds mix: Aspartame; Benzoic Acid; Caffeine; Sorbic Acid NH 2 ОН HO, HO, Benzoic acid Caffeine Sorbic Acid Aspartame

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: 透过率/% 100 20 D 12.1 Which compound is consistent with the spectrum shown below? 薄膜法 4000 1982 8B 26…

A: Infrared (IR) spectroscopy is an analytical technique which is aimed at structural elucidation. Most…

Q: When spiking a sample with isopentyl alcohol, the isopentyl alcohol peak should increase in area on…

A: It is a calibration method that involves adding an additional amount of the substance of interest to…

Q: You are analyzing a forensic sample for the presence of controlled substances using HPLC. Which of…

A: Detector is given.

Q: |1,2,3 Peaks: 5. Ethyl benzoate 6. Toluene 7. 2,6-Dimethoxytoluene 8. o-Methoxybiphenyl 1. Benzyl…

A: Chromatography is the laboratory technique for the separation and isolation of a variety of samples…

Q: Intensity (%) 8- 8- MS - scan #238 (unknown) Scan 238 100%=10,237 Retenlion time 2.61 min. TIC =…

A: The above compound is ethanol. Molecular ion at m/z = 46. Loss of 15 is observed. Loss of hydrogen…

Q: Please identify the compound present in the IR and MS scans. Both scans utilized the same compound.…

Q: None

A: Note that, Plate theory is a simplified model, and real chromatography behavior might deviate…

Q: If you spike the sample you collected with a known amount of the analyte of interest, you are…

A: The objective of the question is to identify the calibration method used when a known amount of the…

Q: Q24) Consider the following data obtained from the size exclusion chromatography of polypropylene,…

A: This is question on molecular weight of polymer

Q: Rel. Intensity 100 80 60 40 20 0.0 0.0 40 MASS SPECTRUM 80 m/z 111 112 120 199 141 104 m/z 141 154…

A: Base peak In mass spectrometry it has highest abundance Base peak fragment is more stable…

Q: Which of the ff. changes is carried out when sample is completely opaque? Prepare 1/10 dilution of…

A: The main aim of this question is to show the sample becomes completely opaque, it means that light…

Q: How can you distinguish between the given compounds using high-resolution mass spectrometry? 1 O CI…

A: In the given question we have to differentiate between the given compounds using high-resolution…

Q: Based on the following Rf values from TLC, explain the similarities and differences between Crude 1…

A: A question based on analytical process that is to be accomplished.

Q: This is a Biochemistry lab question. For the lab we are spectrophotometrically determining the pka…

A: The Beer-Lambert Law states that the log of the ratio of the intensities is equal to the product of…

Q: Consider the following gas chromatography data. Calibration Analysis area of standard 23849 area of…

A: The formula used to find response factor is: Signalanalyte[Analyte] = F * Signalstandard[Standard]

Q: A mixture of A and B is injected into a liquid chromatographic column with length of 24.8 cm. The…

A: Given : Separation resolution between A and B can be calculated using formula: Rs = 2RtB-RtAw1 +…

Q: Mass spectral measurements were made on 10 replicate low concentration Ni-EDTA samples: 191.1,…

Q: Given the mass chromatography, identify the peaks of 200, 144, and 115 for 2-Naphthyl-Butylether.

A: Mass spectroscopy is an analytical technique in which the samples are analyzed based on the…

Q: The intensity of M+, M+1, and M+2 peak are 100.0, 6.8, 31.9. How many carbons are in the compound?…

A: A mass spectrum is an important tool for the determination of the mass of a compound. A mass…

Q: 19. For Ha, how many non-equivalent protons are on the adjacent carbon atoms (that is, how many…

A: 19. For Ha, the number of non-equivalent protons on adjacent carbon is two(Hb ). 20 . n is the…

Q: 110.0 HO (M.H] 162.0 1340

Q: The following questions regard the chromatograms shown below: Which column gives a greater…

Q: In an experiment of Reverse Phase chromatography using C-18 stationary phase and a mixture of…

Q: QUESTION 16 Which list of functional groups is present in the anti viral drug Abidol HO. Br N. OA…

A: Choice B) Thioether, alcohol, ester, amine

Q: Given the following chromatogram of opiates found in urine, determine the separation resolution…

A: We have find out the correct option.

Question

Match the peak chromatogram and the possible compound based on the
information given (example: Peak A – Compound A). All peaks originated from
one HPLC injection.
0.14
Peak 1
Peak 2
0.12-
Peak 3
0.10-
1564
0.08-
1730
1345
Peak 4
0.06-
Peak A
1311
0.04
Рeak B
567
1211
0.02-
0.00-
0.00
0.50
1.00
1.50
2.00
3.00
3.50
4.00
5.00
250
min
4.50
(a) Mode: Normal phase HPLC
Peaks: 1, 2, 3 and 4
Compounds mix: Aspartame; Benzoic Acid; Caffeine; Sorbic Acid
NH 2
H
ОН
ОН
N'
Benzoic acid
Caffeine
Sorbic Acid
Aspartame

(b) Mode: Reverse phase HPLC
Peaks: 1, 2, 3 and 4
Compounds mix: Lipid, carbohydrate, peptide, oligopeptide
ОН ОН
OH
НО
ОН
ОН
carbohydrate
lipid
Но-
HO
H2N,
,.ι ΝΗ 2
HO
NH 2
OH
NH
NH
H2N°
H
H2N'
'N.
H
ОН
peptide
oligopeptide
O IZ
IZ

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step by step

Solved in 5 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

1. A mixture containing 0.500 mM chloroform and 0.800 mM DDT gave signals of 15.3 UA for chloroform and 10.1 uA for DDT. An unknown solution (10.0 mL) containing DDR was places in a 100 mL volumetric flask and 10.2 ul, of chloroform (FM 119.39, density = 1.484 g/mL) were added. After dilution to the mark with solvent, polarographic signals of 29.4 and 8.7 uA were observed for the chloroform and DDT, respectively. Find the concentration of DDT in the unknown.
Provide a structure of the fragment in the mass spec producing the peak at 139 m/z and a structure for the fragment that was lost.
Please correct answer and don't use hand rating
The ppm concentration of Pb2+ in a blood sample were measured with Spectrophotometry. 5.00 mL of a blood sample were taken and this sample gave a signal of 0.301 a.u.. Another 5.00 mL of a blood sample were mixed with 0.50 mL og 1.75 ppm Pb2+. Then, this mixture was diluted to 25.00 mL and this diluted mixture gave a signal of 0.406 a.u.. What is the ppm concentration of a blood sample?
With a resolution of 500 a peak will an m/z value of 297.000 from which of the following peaks? 297.439 297.603 297.356 298.000 297.232