Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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please help find limiting regent given the data
![**Determining the Limiting Reagent in a Chemical Reaction**
When determining the limiting reagent in a chemical reaction, it is crucial to consider the moles of each reactant. The limiting reagent is the reactant that will be completely consumed first, limiting the amount of product that can be formed. In this formula, sulfuric acid is considered a catalyst and does not need to be accounted for in the calculation. Below is a step-by-step explanation using an example reaction:
### Example Reaction
\[ A + B \rightarrow C \]
#### Calculation
1. **Determine moles of Reactant A**:
\[
\text{Given: } 20.00 \text{ g of } A
\]
Using the molar mass (MW) of \(A\):
\[
20.00 \text{ g } \times \left( \frac{1 \text{ mol A}}{\text{MW A}} \right) = \text{mole ratio of A}
\]
Hence, this can be represented as:
\[
20.00 \text{ g A } \times \left(\frac{1 \text{ mol A}}{\text{MW A}}\right) \times \left(\frac{1 \text{ mol A}}{1 \text{ mol A}}\right) = \text{mole ratio of A}
\]
In this example, we are calculating the mole ratio for reactant A. The same steps should be repeated for reactant B to determine its mole ratio. The reactant with the lower mole ratio will be the limiting reagent.
This method provides a systematic way to identify the reagent that limits the formation of the product \(C\) in the given chemical reaction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6746fa6f-1856-443b-addc-ecae5d9da9b9%2F492dd69f-89cf-4b12-8948-d5be99b36a6f%2Fu6nslap_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Determining the Limiting Reagent in a Chemical Reaction**
When determining the limiting reagent in a chemical reaction, it is crucial to consider the moles of each reactant. The limiting reagent is the reactant that will be completely consumed first, limiting the amount of product that can be formed. In this formula, sulfuric acid is considered a catalyst and does not need to be accounted for in the calculation. Below is a step-by-step explanation using an example reaction:
### Example Reaction
\[ A + B \rightarrow C \]
#### Calculation
1. **Determine moles of Reactant A**:
\[
\text{Given: } 20.00 \text{ g of } A
\]
Using the molar mass (MW) of \(A\):
\[
20.00 \text{ g } \times \left( \frac{1 \text{ mol A}}{\text{MW A}} \right) = \text{mole ratio of A}
\]
Hence, this can be represented as:
\[
20.00 \text{ g A } \times \left(\frac{1 \text{ mol A}}{\text{MW A}}\right) \times \left(\frac{1 \text{ mol A}}{1 \text{ mol A}}\right) = \text{mole ratio of A}
\]
In this example, we are calculating the mole ratio for reactant A. The same steps should be repeated for reactant B to determine its mole ratio. The reactant with the lower mole ratio will be the limiting reagent.
This method provides a systematic way to identify the reagent that limits the formation of the product \(C\) in the given chemical reaction.
Transcribed Image Text:**Data for Methyl Esterification Experiment**
**Mass of Benzoic Acid Used:** 5.040 grams
**Volume of Methanol Used:** 12.0 mL
**Mass of Methyl Benzoate Obtained:** 4.810 grams
(Note: There are no graphs or diagrams associated with this data.)
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