Calculate the standard enthalpy of formation of acetylene (C2H2) from its elements: 2C(graphite) + H₂(g) → C₂H₂ (9) 22 The equations for each step and the corresponding enthalpy changes are: (b) (c) CO₂(g) H₂(g) + O₂(g) -H₂O(1) AH 2C₂H₂(g) + 5O₂(g) →→→ 4CO₂(g) + 2H₂O(1) AH C(graphite) + O₂(g) AH-393.5 kJ/ = -285.8 kJ/ = -2598.8 kJ

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the standard enthalpy of formation of acetylene (C2H2) from its
elements:
The equations for each step and the corresponding enthalpy changes are:
(a)
(b)
(c)
2C(graphite) +
+ H₂(g) → C₂H₂ (g)
22
C(graphite) + O₂(g) → CO₂(g)
AH-393.5 kJ/mol
H₂(g) + O₂(g)
H₂O(1)
AH-285.8 kJ/mol
2C₂H₂(g) + 50₂(g)
4CO₂(g) + 2H₂O(1) AH = -2598.8 kJ/mol
5.4. Using the Hess Law, what will be the new chemical equation of the equation
(b)?
0 0 0 0
Oa. H2 + 02 -> HO2
b. H2+½ 02-> H20
Oc. 2H02->2H2 +02
Od 2H2+02->2H20
€
Transcribed Image Text:Calculate the standard enthalpy of formation of acetylene (C2H2) from its elements: The equations for each step and the corresponding enthalpy changes are: (a) (b) (c) 2C(graphite) + + H₂(g) → C₂H₂ (g) 22 C(graphite) + O₂(g) → CO₂(g) AH-393.5 kJ/mol H₂(g) + O₂(g) H₂O(1) AH-285.8 kJ/mol 2C₂H₂(g) + 50₂(g) 4CO₂(g) + 2H₂O(1) AH = -2598.8 kJ/mol 5.4. Using the Hess Law, what will be the new chemical equation of the equation (b)? 0 0 0 0 Oa. H2 + 02 -> HO2 b. H2+½ 02-> H20 Oc. 2H02->2H2 +02 Od 2H2+02->2H20 €
5.5. What rule of Hess Law is being applied in equation (b)?
a. Rule 1
O b. Rule 2
O c. Rule 3
O d. No rules applied.
5.6. What is the new enthalpy of equation (b)
O a. 285.8kJ
O b.-285.8kJ
O c. 571.6kJ
O d. -571.6kJ
Transcribed Image Text:5.5. What rule of Hess Law is being applied in equation (b)? a. Rule 1 O b. Rule 2 O c. Rule 3 O d. No rules applied. 5.6. What is the new enthalpy of equation (b) O a. 285.8kJ O b.-285.8kJ O c. 571.6kJ O d. -571.6kJ
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