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- Man with mass of (10 Kg ) standing on the one leg
has a (1 M) shaft of bone with average cross-
sectional area of ( 4 cm^2) find the amount of
shortening in this bone(1.8 x 10^10 N/m)
A.
4-A10*0.138
В.
4-^10*0.231
C.
4-^10*3
D.
4-^10
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