You apply a force of magnitude F1 to one end of a wire and another force F in the opposite direction to the other end of the wire. The cross-sectional area of the wire is 8.00 mm2. You measure the fractional change in the length of the wire, Al/lo. for several values of F. When you plot your data with Al/lo on the vertical axis and F (in units of N) on the horizontal axis, the Part A What is the value of Young's modulus for this wire? data lie close to a line that has slope 8.0 x 10-7N-1 Express your answer with the appropriate units. Y = Value Units Submit Request Answer
You apply a force of magnitude F1 to one end of a wire and another force F in the opposite direction to the other end of the wire. The cross-sectional area of the wire is 8.00 mm2. You measure the fractional change in the length of the wire, Al/lo. for several values of F. When you plot your data with Al/lo on the vertical axis and F (in units of N) on the horizontal axis, the Part A What is the value of Young's modulus for this wire? data lie close to a line that has slope 8.0 x 10-7N-1 Express your answer with the appropriate units. Y = Value Units Submit Request Answer
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Physics And Measurement
Section: Chapter Questions
Problem 1.67AP: A rod extending between x = 0 and x = 14.0 cm has uniform cross-sectional area A = 9.00 cm2. Its...
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![## Item 18
**Scenario:**
You apply a force of magnitude \( F_1 \) to one end of a wire and another force \( F_1 \) in the opposite direction to the other end of the wire. The cross-sectional area of the wire is \( 8.00 \, \text{mm}^2 \). You measure the fractional change in the length of the wire, \( \Delta l / l_0 \), for several values of \( F_1 \). When you plot your data with \( \Delta l / l_0 \) (in units of N) on the vertical axis and \( F_1 \) (in units of N) on the horizontal axis, the data lie close to a line that has a slope \( 8.0 \times 10^{-7} \, \text{N}^{-1} \).
### Part A
**Question:**
What is the value of Young's modulus for this wire?
**Instructions:**
Express your answer with the appropriate units.
### Input Field
- **Value:** Text box to enter the numerical value of Young's modulus.
- **Units:** Drop-down menu to select the appropriate units.
### Submit Button:
- **Submit:** Button to submit the answer.
- **Request Answer:** Button to request the correct answer if unsure.
### Additional Options:
There are various tools and icons designed to help the user format their answer, including equation editors and help functions.
### Feedback:
A link to provide feedback on the problem is available at the bottom of the interface.
**Graphical Interpretation:**
- The question implies a linear relationship between \( \Delta l / l_0 \) and \( F_1 \), with the given slope \( 8.0 \times 10^{-7} \, \text{N}^{-1} \).
### Calculation Tip:
To find Young's modulus (\( Y \)), use the formula:
\[ Y = \frac{F/A}{\Delta l / l_0} \]
Given the problem's slope as \( 8.0 \times 10^{-7} \, \text{N}^{-1} \) and the cross-sectional area \( A = 8.00 \, \text{mm}^2 \).
Ensure proper conversion of units as needed and input the value accordingly in the fields provided.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffc3dd7c1-8afd-440d-b1a8-adfb002a6744%2F73dc87ae-25c9-45e4-8033-02fc351f3563%2Fr5pm5i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:## Item 18
**Scenario:**
You apply a force of magnitude \( F_1 \) to one end of a wire and another force \( F_1 \) in the opposite direction to the other end of the wire. The cross-sectional area of the wire is \( 8.00 \, \text{mm}^2 \). You measure the fractional change in the length of the wire, \( \Delta l / l_0 \), for several values of \( F_1 \). When you plot your data with \( \Delta l / l_0 \) (in units of N) on the vertical axis and \( F_1 \) (in units of N) on the horizontal axis, the data lie close to a line that has a slope \( 8.0 \times 10^{-7} \, \text{N}^{-1} \).
### Part A
**Question:**
What is the value of Young's modulus for this wire?
**Instructions:**
Express your answer with the appropriate units.
### Input Field
- **Value:** Text box to enter the numerical value of Young's modulus.
- **Units:** Drop-down menu to select the appropriate units.
### Submit Button:
- **Submit:** Button to submit the answer.
- **Request Answer:** Button to request the correct answer if unsure.
### Additional Options:
There are various tools and icons designed to help the user format their answer, including equation editors and help functions.
### Feedback:
A link to provide feedback on the problem is available at the bottom of the interface.
**Graphical Interpretation:**
- The question implies a linear relationship between \( \Delta l / l_0 \) and \( F_1 \), with the given slope \( 8.0 \times 10^{-7} \, \text{N}^{-1} \).
### Calculation Tip:
To find Young's modulus (\( Y \)), use the formula:
\[ Y = \frac{F/A}{\Delta l / l_0} \]
Given the problem's slope as \( 8.0 \times 10^{-7} \, \text{N}^{-1} \) and the cross-sectional area \( A = 8.00 \, \text{mm}^2 \).
Ensure proper conversion of units as needed and input the value accordingly in the fields provided.
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