mally consolidated clay samples having a diameter of 50 mm. and height of 25 mm. Normal force (N) Shear force at Test no. fallure (N) 67 23.3 2 133 46.6 44.6 132.3 3 213 369 4 Draw a graph for shear stress at failure against the normal stress and determine the drained angle of friction from the graph. 12.5 Repeat Problem 12.4 with the following data. Given: Specimen diameter = 50 mm; specimen height = 25 mm. Normal force (N) Shear force at fallure (N) Test no. 250 139 375 209 450 540 250 300 234 Ceng age Leaming 2014 © Cengage leerning 201 4

mally consolidated clay samples having a diameter of 50 mm. and height of 25 mm. Normal force (N) Shear force at Test no. fallure (N) 67 23.3 2 133 46.6 44.6 132.3 3 213 369 4 Draw a graph for shear stress at failure against the normal stress and determine the drained angle of friction from the graph. 12.5 Repeat Problem 12.4 with the following data. Given: Specimen diameter = 50 mm; specimen height = 25 mm. Normal force (N) Shear force at fallure (N) Test no. 250 139 375 209 450 540 250 300 234 Ceng age Leaming 2014 © Cengage leerning 201 4

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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7.12 A sand specimen was subjected to a drained shear test using hollow cylin- der test equipment. Failure was caused by increasing the inside pressure while keeping the outside pressure constant. At failure, o, = 193 kN/m² and o; = 264 kN/m². The inside and outside radii of the specimen were 40 and 60 mm, respectively. (a) Calculate the soil friction angle. (b) Calculate the axial stress on the specimen at failure.
A series of direct shear tests were conducted on a sample of soil in a 60 mm square shear box. The table below shows the results that were obtained at failure. Plot the graph of shear stress at failure against normal stress anddetermine the strength parameters of the soil. Normal Load (N) 200 300 400 Shear Load (N) 105 142 180
in a drained triangle test on consolidated clay the stress and angle area as follows deviator stress is 20 lb/ in ^2 and friction angle is 21 degree calculate the effective confining pressure at failure
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x 18 The effective shear strength equation (S = T₁ = 25+5 tam 30); expressed for a saturated clayey soil. In undrained test on a sample of the same soil using the shear box apparatus, the following data at failure were recorded :. Shear Stress = 90 kPa a) What and Normal stress = 180 kPa pore water pressure in the specimen at time of was the failure (assume Øu= 0). Find the Unconfined compressive strength (Od max) for the same soil an Unconfined. when tested in Compression test. c) Find the major principal stress when a sample of the same soil is tested in Ul test with confining pressure of (200 kPa).
1.A dry sand is known to have an angle of internal friction of 29. A triaxial test is planned, where the confining pressure will be 41 kPa. What is the maximum axial stress, in kPa, (major principal stress) that can be applied? Calculate the value to 1 decimal place. Do not provide units in your answer. 2.A clay soil is subjected to a triaxial test under unconsolidated-undrained conditions. At failure, the major and minor principal stresses are 8401 psf and 4875 psf, respectively. What is the shear strength of this soil if the confining pressure is doubled? Provide your answer in psf with no decimals.
a sample of dry sand is tested in direct shear. the shear box holding the same has a circular cross section with a diameter of 50 mm. The normal compressive load imposed is 200N. The sample shears when the shear force is 120N. Compute the Normal stress, Shear test at failure Angle ofninternal friction of this soil.
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A sample of sand is sheared in the following manner. First an all around normal stresso 350 kPa is applied to the sample. Next a shear stress is applied to the horizontal pia while the normal stress remains constant. The shear stresses at failure are + 186 kPa. Ihe initial stress and stress condition at failure are shown below 350 kPa 350 kPa 186 kPa 350 kPa 350 kPa ー550 kPa 550 kPa 186 kPa 350 kPa 350 kPa Initial Conditions At Failure Determine the Following: fo A) Assuming c, = 0, draw a failure envelope for the soil. Define the friction angle ( the soil. B) Draw the Mohr's Circle at failure for the test. C) Show the location of the pole. D) Define the maximum and minimum principal stresses at failure. E) Define the normal stress corresponding to the maximum shear stress
Soil sample size is (21cm×21cm)
Question A sample of dry sand was tested in direct shear test apparatus under a normal load of 72 kg. The shear load required to fail the sample was found to be 36 kg. The angle of internal friction () will be:
A soil specimen is subjected to a tri – axial test. The soil specimen is cohesionless. If the shear stress that causes failure is 300 kPa. and the normal stress at failure is only 500 kPa 5. Determine the angle of shearing resistance in degrees 6. Determine the angle that the failure plane measured from the major principal plane. 7. Determine the total axial stress in kPa at which failure is expected to occur.