magnesium metal foil was illuminated by a pulse of laser beam with a wavelength of 306 nm. A total number of 6 x 10³ ejected electrons were generated. Each electron has an de Broglie wavelength of 2 nm. (a) Calculate the work function (express the answer in eV) (b) Calculate the threshold frequency (express the answer in nm).
magnesium metal foil was illuminated by a pulse of laser beam with a wavelength of 306 nm. A total number of 6 x 10³ ejected electrons were generated. Each electron has an de Broglie wavelength of 2 nm. (a) Calculate the work function (express the answer in eV) (b) Calculate the threshold frequency (express the answer in nm).
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Author:Raymond A. Serway, Chris Vuille
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answer parts a and b

Transcribed Image Text:magnesium metal foil was illuminated by a pulse of laser beam with a wavelength of 306 nm. A
total number of 6 × 10³ ejected electrons were generated. Each electron has an de Broglie
wavelength of 2 nm.
(a) Calculate the work function (express the answer in eV)
(b) Calculate the threshold frequency (express the answer in nm).
Expert Solution

Step 1: de Broglie relation and Photoelectric effect formula
The de Broglie wavelength () of a particle with momentum
is given by:
where is Planck's constant (
J·s) and
is the momentum of the particle.
The photoelectric effect relates the energy of a photon to the work function () and the kinetic energy of the emitted electron (
):
Given that , where
is Planck's constant and
is the frequency of the incident light.
The kinetic energy () of the emitted electron can be expressed in terms of its velocity (
) as:
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