Question 6: Consider the following situation: A thin circular ring of radius R has a charge +Q uniformly distributed on the entire loop. a) What is the value of the electric potential at a point a distance r from the center of the ring along the axis that passes through the center of the ring? b) Calculate the electric field created from the ring using the potential you found in part (a). You should compare this to the electric field you found previously from direct integration in Homework Set 05.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please solve A and B

Question 6: Consider the following situation:
A thin circular ring of radius R has a charge +Q uniformly
distributed on the entire loop.
a) What is the value of the electric potential at a point a
distance r from the center of the ring along the axis that
passes through the center of the ring?
"P
b) Calculate the electric field created from the ring using
the potential you found in part (a). You should compare
this to the electric field you found previously from direct
integration in Homework Set 05.
Transcribed Image Text:Question 6: Consider the following situation: A thin circular ring of radius R has a charge +Q uniformly distributed on the entire loop. a) What is the value of the electric potential at a point a distance r from the center of the ring along the axis that passes through the center of the ring? "P b) Calculate the electric field created from the ring using the potential you found in part (a). You should compare this to the electric field you found previously from direct integration in Homework Set 05.
Expert Solution
Step 1

Given that:

Radius of the ring = R

Charge on the ring = Q

Let center of circle be pointed as O and the upper point be A , so it make a triangle AOP

AP = R

OP = x

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