Macmillan Learning What is the concentration of a solution made by diluting 75 mL of 6.0 M HCl to a final volume of 750 mL? concentration: M

Q: What volume of concentrated HCI (12 M) solution needs to be diluted to produce 275 mL of 2.1 M HCI…

A: Since we know that  M1V1 = M2V2 Where ,  M1 = initial concentration  V1= initial volume  M2= final…

Q: Calculate the mass-volume percent concentration for a 8.7 M NaOH solution.  ____%

A: The mass/volume percent of a solution is defined as the ratio of the mass of solute that is present…

Q: 200 mL of water is added to 700 mt of a 3-M NaCI solution. What is the concentration of the diluted…

A: Given that : Volume of Water (V2) = 700mL + 200 mL = 900mL Volume of NaCl (V1) = 700 mL…

Q: What volume of a 0.24 M malonic acid solution contains 0.006 mc malonic acid? 1.4 L 0.025 L not…

A: Given, molarity of solution= 0.24 M  Moles of acid = 0.006

Q: It takes 24.35 mL of a 0.35 M HCI solution to neutralize 36.44 mL of NaOH solution. Calculate the…

A: The molarity of NaOH solution can be calculated as

Q: What is the concentration of a solution made by diluting 85 mL of 6.0 M HCl to a final volume of 750…

A: Given values are, N1= 6.0 M V1= 85mL V2= 750 mL N2=?

Q: What volume of a 0.343 M HCl solution is required to neutralize 24.0 mL of NaOH a 0.123 M  solution?…

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Q: What concentration of 29.03 mL of H2SO4 can be prepared from 13.53 mL of 0.45 M H2SO4?

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Q: You are instructed to prepare 250 mL of a solution that is 2.5 M NaOH. You have available a stock…

A: Given that:  Molarity of stock NaOH(M1) = 15.5M  Molarity of final NaOH solution(M2) = 2.5M Volume…

Q: What volume of 12.0 M HCI (concentrated HCI) would you need to make 1.00L of 1.0M HCI? A B C D 83.3…

A: This question belong to some basic concepts of chemistry that is Mole Concept. Solve by using…

Q: What is the concentration of a solution made by diluting 25 mL of 6.0 M HC to a final volume of 750…

A: The molarity is a concentration term defined as the number of moles of solute per liter volume of…

Q: In Standardization of 10 ml NaOH solution with HCI solution, if we consumed 35 ml of 0.4 M HCI, The…

A: Ans Titration reaction of the NaOH wth HCl NaOH + HCl  ------------------> NaCl + H2O Now one…

Q: if u add 400.0 mL of water to 50.0 mL of 6.0 M HCl what is new concentration

A: Initial volume = 50.0 ml initial concentration = 6.0M Final volume = 400+ 50 = 450 millilitre

Q: Suppose that 15.0 ml of 0.0250M aqueous H2SO4 is required to neutralize 10.0 ml of an aqueous…

A: The number of moles of solute dissolved in per liter volume of solution is termed as MOLARITY. It is…

Q: #6 If I have 340. mL of a 0.5 M NaBr solution, what will the concentration be if I add 560.0 mL more…

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Q: What is the concentration of a solution made by diluting 35 mL of 6.0 M HCl to a final volume of 750…

A:

Q: You need to prepare a solution of glycerol ( CH2OH-CHOH-CH2OH ) in 100.0 g of water, so the…

A: Molality (m) : molality is defined as the no of moles of solute present in given mass of solvent…

Q: Using table 3, answer the following questions.  Concentration of HCl (M) 1.0M Volume HCl (mL)…

A:

Q: If I have 340 mL of a 0.500 M NaBr solution, what will the concentration be if I add 560 mL more…

A: Initial volume = 340 mLInitial concentration = 0.500 MFinal volume =

Q: How many grams of AgNO3 should be present per liter of solution so that each mL is equivalent to 1.0…

A: We will first calculate number of equivalents of Cl- , then using it calculate mass of AgNO3 in 1 ml…

Q: 5. Which of the following solutions will have the greatest concentration of S? A. 150.0 mL of 0.010M…

A: Molarity is a specific type of concentration measurement used in chemistry to describe the amount of…

Q: ▼ Part A What is the concentration (M) of CH3OH in a solution prepared by dissolving 17.6 g of CH3OH…

A: 1) Mass of solute CH3-OH= 17.6 gm2) Molar mass of CH3OH = 32.04 g/mol3) Volume of solution = 230 ml…

Q: What is the concentration of a solution made by diluting 55 mL of 6.0M HCl to a final volume of 750…

A: The following question can be solved by using the rule which states that after dilution the moles…

Q: What is the concentration of a solution made by diluting 95 mL of 6.0 M HCl to a final volume of 750…

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Q: How many millilitres of 0.152 mol L HCIO, solution are needed to neutralize 50.00 ml of 0.0793 mol L…

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Q: What is the molarity of a solution of H2SO4  if 25 mL of this solution requires 32.15 mL of a 0.600…

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Q: What volume of 0.25 M hydrochloric acid (HCI) solution contains 0.15 mol HCI? Select one: a. 1.7 L…

A:

Q: How many grams of NaOH must be added to 1.00 L of water to make a 15.0% NaOH solution?

A: Given data: The volume of solution = 1 L  %wV = 15.0 %

Q: A 120.0 mL sample of a 0.81 M H2SO4 solution is diluted with enough water to reduce the…

A: On dilution the number of moles remain equal in concentrated solution and diluted solution. Volume…

Q: What is the concentration of H+ in a 2.5 M HCl solution?  a. 2.5 M b. 1.3 M c. 1.0 M d. 5.0 M

A: Correct answer is (a) 2.5 M. HCl -----> H+  + Cl-  By stoichiometry of reaction: [H+] = [HCl] =…

Q: If I dilute 250 mL of 0.10 M lithium acetate solution to a volume of 750 mL, what will the…

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Q: What is the concentration of a solution made by diluting 15 mL of 6.0 M HCl to a final volume of 750…

A: Given, Initial concentration of HCl solution, C1 = 6.0 M Initial volume of HCl solution, V1 = 15 mL…

Q: About 21.60 mL of 0.9944N sodium hydroxide solution required 20.40 mL of hydrochloric acid solution.…

A: Given information: 21.60 mL of 0.9944 N sodium hydroxide (NaOH) requires for 20.40 mL of…

Q: A 1:20 dilution is done with a 0.2500 M Na,SO4 solution. What is the concentration of the diluted…

A: Dilution is done to decrease the  concentration  of solution .

Q: A solution is prepared by dissolving 5.21 g of ammonium sulfate in enough water to make 100.0 ml of…

A: Given : Mass of ammonium sulfate i.e (NH4)2SO4 = 5.21 g And volume of solution = 100.0 mL = 0.100 L…

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.