A 67.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 288 mL. A 144 mL portion of that solution is diluted by adding 181 mL of water. What is the final concentration? Assume the volumes are additive.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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A 67.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 288 mL. A 144 mL portion of that solution is diluted by adding 181 mL of water. What is the final concentration? Assume the volumes are additive.

concentration: [input box] M

**Explanation:**

This exercise involves understanding dilution and concentration calculations in chemistry. Here, a solution is subjected to two dilution steps, and we need to determine the final concentration after these processes. Dilutions can be calculated using the formula \( C_1V_1 = C_2V_2 \), where \( C \) is the concentration and \( V \) is the volume. The challenge is to apply this formula in a stepwise manner to derive the final concentration.
Transcribed Image Text:**Educational Website Text:** A 67.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 288 mL. A 144 mL portion of that solution is diluted by adding 181 mL of water. What is the final concentration? Assume the volumes are additive. concentration: [input box] M **Explanation:** This exercise involves understanding dilution and concentration calculations in chemistry. Here, a solution is subjected to two dilution steps, and we need to determine the final concentration after these processes. Dilutions can be calculated using the formula \( C_1V_1 = C_2V_2 \), where \( C \) is the concentration and \( V \) is the volume. The challenge is to apply this formula in a stepwise manner to derive the final concentration.
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