A 67.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 288 mL. A 144 mL portion of that solution is diluted by adding 181 mL of water. What is the final concentration? Assume the volumes are additive.
A 67.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 288 mL. A 144 mL portion of that solution is diluted by adding 181 mL of water. What is the final concentration? Assume the volumes are additive.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A 67.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 288 mL. A 144 mL portion of that solution is diluted by adding 181 mL of water. What is the final concentration? Assume the volumes are additive.
concentration: [input box] M
**Explanation:**
This exercise involves understanding dilution and concentration calculations in chemistry. Here, a solution is subjected to two dilution steps, and we need to determine the final concentration after these processes. Dilutions can be calculated using the formula \( C_1V_1 = C_2V_2 \), where \( C \) is the concentration and \( V \) is the volume. The challenge is to apply this formula in a stepwise manner to derive the final concentration.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fabe9e786-be4a-454e-b2cf-16d08b96c793%2F6ce47d2c-ef3c-46fe-81f5-58a30ce639b2%2Fdho80mr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Educational Website Text:**
A 67.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 288 mL. A 144 mL portion of that solution is diluted by adding 181 mL of water. What is the final concentration? Assume the volumes are additive.
concentration: [input box] M
**Explanation:**
This exercise involves understanding dilution and concentration calculations in chemistry. Here, a solution is subjected to two dilution steps, and we need to determine the final concentration after these processes. Dilutions can be calculated using the formula \( C_1V_1 = C_2V_2 \), where \( C \) is the concentration and \( V \) is the volume. The challenge is to apply this formula in a stepwise manner to derive the final concentration.
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