**Title: Preparing Solutions Using a Standard NaOH Solution**----**Instructions:**Be sure to answer all parts.**Problem Statement:**How many milliliters of a 7.87 M NaOH solution would be needed to prepare each solution?**a.** Prepare a volume of 585 mL of a 1.62 M solution.*Required: _______ mL***b.** Prepare a volume of 420 mL of a 0.516 M solution.*Required: _______ mL*----**Instructions for Solving:**To determine the required volume of the standard 7.87 M NaOH solution to prepare each of the new solutions, use the dilution formula:\[ C_1V_1 = C_2V_2 \]Where:- \( C_1 \) = concentration of stock solution (7.87 M)- \( V_1 \) = volume of stock solution needed- \( C_2 \) = concentration of desired solution- \( V_2 \) = volume of desired solutionCalculate \( V_1 \) for each scenario to find the answer.

Given: The volume of the stock solution of NaOH = 7.87 M We have to find how many milliliters of this NaOH solution would be required to prepare a. 585 mL of a 1.62 M solution b. 420 mL of a 0.516 M solution

Answered: Be sure to answer all parts. How many…

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Be sure to answer all parts. How many milliliters of a 7.87 M NAOH solution would be needed to prepare each solution? a. 585 mL of a 1.62 M solution mL b. 420 mL of a 0.516 M solution mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Title: Preparing Solutions Using a Standard NaOH Solution**

----

**Instructions:**

Be sure to answer all parts.

**Problem Statement:**

How many milliliters of a 7.87 M NaOH solution would be needed to prepare each solution?

**a.** Prepare a volume of 585 mL of a 1.62 M solution.

*Required: _______ mL*

**b.** Prepare a volume of 420 mL of a 0.516 M solution.

*Required: _______ mL*

----

**Instructions for Solving:**

To determine the required volume of the standard 7.87 M NaOH solution to prepare each of the new solutions, use the dilution formula:

\[ C_1V_1 = C_2V_2 \]

Where:

- \( C_1 \) = concentration of stock solution (7.87 M)
- \( V_1 \) = volume of stock solution needed
- \( C_2 \) = concentration of desired solution
- \( V_2 \) = volume of desired solution

Calculate \( V_1 \) for each scenario to find the answer.

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