ما3 Consider Ho: U = 31 versus H₁: #31. A random sample of observations taken from this population produced a sample mean of The population is normally distributed with a = 27.70 Note: Use Table IV in Appendix C to compute the probabilities. (a) Calculate the p-value. (b) Considering the p-value of part (a), would you reject the null hypothesis if the test were made at the significance level of 0.05? (c) Considering the p-value of part (a). would you reject the null hypothesis if the test were made at the significance level of 0.01?
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- 7To estimate u, the mean salary of full professors at American colleges and universities, you obtain the salaries of a random sample of 400 full professors. The sample mean is x = $73,220 and the sample standard deviation is s = $4400. Which of the following conditions is NOT required to construct a 90% confidence interval for u? Oa random 10n SN np 2 10 and n(1-p) 210 n2 30 or stated as normalWe have provided a sample mean, sample size, and population standard deviation. In each case, use the one-mean z-test to perform the required hypothesis test at the 5% significance level. x = 20, n = 24, σ = 4, H0: μ = 22, Ha: μ ≠ 22
- Test the claim about the differences between two population variances a and o at the given level of significance a using the given sample statistics. Assume that the sample statistics are from independent samples that are randomly selected and each population has a normal distribution. Claim: o so, a = 0.05 Sample statistics: s, = 705, n, =3, s = 368, n, = 9 Find the null and alternative hypotheses. OA Hoio> Hạ: o so3 OC. Hoi o z0 H,: oIs the answer (I) We REJECT Ho at the 0.05 significance level. OR (II) We FAIL TO REJECT Ho at the 0.05 significance level.3Under what circumstances is a t statistic used instead of a z-score for a hypothesis test? Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. Determine the critical region using a one-tailed test with alpha = .05. Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). Based on your analysis, is there a relationship between the drug and attention span?Use the given statistics to complete parts (a) and (b). Assume that the populations are normally distributed. (a) Test whether u, >uz at the a = 0.05 level of significance for the given sample data. (b) Construct a 99% confidence interval about u1 -P2. Population 2 23 Population 1 22 46.4 41.8 4.3 13.1 (a) Identify the null and alternative hypotheses for this test. O A. Ho: H1 = H2 H1: H1 # H2 O B. Ho: H1 =H2 H1: H1 H2 OF. Ho: H1 > H2 H1: H1 = H2 Find the test statistic for this hypothesis test. (Round to two decimal places as needed.)Test the claim about the population variance o² at the level of significance α. Assume the population is normally distributed. Claim: o² ≥8.5; α = 0.10 2 Sample statistics: s² = 7.78, n = 25 Write the null and alternative hypotheses. Ho: 0² ≥ 8.5 Ha: 0² < 8.5 (Type integers or decimals. Do not round.) Calculate the standardized test statistic. x² = 21.97 (Round to two decimal places as needed.) Determine the P-value. P-value = (Round to three decimal places as needed.)A data set about speed dating includes "like" ratings of male dates made by the female dates. The summary statistics are n=186, x=6.55, s=2.05. Use a 0.05significance level to test the claim that the population mean of such ratings is less than 7.00.Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.(2) Choose the one alternative that best completes the statement or answers the question. Assume two independent random samples are available which provide sample proportions. For the first sample assume n₁ = 100 and x₁= 39. For the second sample, assume n₂= 100 and x₂= 49. Test the null hypothesis that the population proportions are equal versus the alternative hypothesis that the proportions are not equal at the 90% confidence level. Frame the test statistic by subtracting the proportion for population 1 from that for population 2. Pick an appropriate z value, p-value and conclusion. Round your answer to the nearest thousandth. Note that this is a two- tailed test. z-value = -1.425 p-value= 0.077 statistically significant z-value = 1.425 p-value= 0.077 statistically significant z-value = -1.425 p-value= 0.077 not statistically significant z-value = 1.425 p-value= 0.154 statistically not significantTest the hypotheses shown below for a random sample with s = 140 and n= 28 at the 5% significance level. Họ: os 100 H,: o?> 100 Click the icon to view the upper critical values of Chi-square distribution table. For this test at the significance level a with sample variance s, hypothesized variance o, sample size n, and critical value x2: X-11- or x4g/2 and x11-g/2: what is the form of the decision rule? (n-1)s2 (n- 1)s? O A. Reject H, if > Xn-1g/2 or reject H, if 1-1,1-a/2 (n- 1)s2 O B. Reject Ho if (n- 1)s? Oc. 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