MA 58. How many moles of Fe₂O3 are produced if you begin with 5.6 moles of Fe? 9.Lem X 2 1 Zm 59. If you react 0.78 grams of O₂, how many moles of Fe₂O3 can you produce? 0.7890 2 | x 178902 60. You end up with 2.31 grams of Fe₂O3. How many grams of Fe must you have started with?

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Mole Highway
Molar Mass
Mole Ratio
(from Balanced
Equation)
Mass
Moles
Molar Mass
Mass
A
Moles
B
A
B
For questions 56-58, use the balanced chemical reaction below. You will need to calculate the molar
mass of some compounds.
4 Fe +3 0₂2 Fe₂O3
MB
MA
58. How many moles of Fe₂O3 are produced if you begin with 5.6 moles of Fe?
1
S. Lem
X
1
zm
59. If you react 0.78 grams of O₂, how many moles of Fe₂O3 can you produce?
0.7890 2
x
1
178902
60. You end up with 2.31 grams of Fe₂O3. How many grams of Fe must you have started with?
8
Transcribed Image Text:Mole Highway Molar Mass Mole Ratio (from Balanced Equation) Mass Moles Molar Mass Mass A Moles B A B For questions 56-58, use the balanced chemical reaction below. You will need to calculate the molar mass of some compounds. 4 Fe +3 0₂2 Fe₂O3 MB MA 58. How many moles of Fe₂O3 are produced if you begin with 5.6 moles of Fe? 1 S. Lem X 1 zm 59. If you react 0.78 grams of O₂, how many moles of Fe₂O3 can you produce? 0.7890 2 x 1 178902 60. You end up with 2.31 grams of Fe₂O3. How many grams of Fe must you have started with? 8
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