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m1 m2 Figure P7.66 Problems 66 and 67. 67. * Again consider the track and carts in Figure P7.66 with 10 kg and m2 20 kg, but this time the carts stick together m1 after the collision. (a) Find the height h from which cart 1 would need to start to make sure that both carts complete the loop without leaving the track. (b) Find the height needed if instead the more massive cart is made to collide with the smaller cart.

m1 m2 Figure P7.66 Problems 66 and 67. 67. * Again consider the track and carts in Figure P7.66 with 10 kg and m2 20 kg, but this time the carts stick together m1 after the collision. (a) Find the height h from which cart 1 would need to start to make sure that both carts complete the loop without leaving the track. (b) Find the height needed if instead the more massive cart is made to collide with the smaller cart.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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This is from a physics 101 class. The equation sheet is attached and so is the problem 67 only part a. It is a physics question and not a writing question. Has to do with motion and energy. You must start with an equation on the equation sheet and build the answer off of that. Please show all steps and algebra. I do not receive credit if solution is not built from equation from equation sheet.
Physics 103 Equation Sheet G=6.67 x 1011 Nm²/kg² O = 5.67 x 10% W/m?K* Pwater = 1.0 x 103 kg/m3 Pair = 1.29 kg/m³ g = 9.8 m/s? = 32 ft/s? k = 1.38 x 1023 J/K Piron = 7.87 x 10³ kg/m³ Paluminum = 2.7 x 10³ kg/m3 Patm = 1.01 x 10$ N/m? MEarth = 5.98 x 1024 kg Pseawater = 1.03 x 103 kg/m³ Pice = 0.92 x 10³ kg/m³ cos 8 = adj/hyp sin e = opp/hyp a? + b? = c? tan 0 = opp/adj -b ±Vb² – 4ac 2a Ax v = At Δν a = At Δω a = At V = Vọ + at v = vo? + 2a(x-xo) Aw Δt x = Xo + Vot + ½ at? EF = ma T = Fr sin 0 Frr S uN ac = v/r Στ- Ια Fg = w = mg Gm,m2 F Fb = pVsubg Fsp = -kAx r2 p = m/V Vave = (AP r)/8nL P = Po+ pgh P = F/A VIA1 = V2A2=AV/At Pi+pghi+% pv?= P2+pgh2+½ pv,? W = FAr cos 0 KE1+ PE1 = KE2+ PE2 – Wnc P = W/At FAt = Ap Wnet = AKE PEg = mgh KE = % mv? PESP = % k Ax? p = mv E = mc? Momentum T2- T1 = KA = oɛA(T – T) AS = R=L/K Q = mc AT KEave = 3/2 kT Q = mL PV = NkT AU = Q- W W = P AV thermeff = 1-Tc/TH Cannot Start with these but hey are ane) to build to using above Fnet - WMA =MAV/AT Must start with equahon above the line on top and buld from there showing all Steps. and manialaton of formcdas. Fnet AT AmV AP-AmV- Fnet OT
Transcribed Image Text:Physics 103 Equation Sheet G=6.67 x 1011 Nm²/kg² O = 5.67 x 10% W/m?K* Pwater = 1.0 x 103 kg/m3 Pair = 1.29 kg/m³ g = 9.8 m/s? = 32 ft/s? k = 1.38 x 1023 J/K Piron = 7.87 x 10³ kg/m³ Paluminum = 2.7 x 10³ kg/m3 Patm = 1.01 x 10$ N/m? MEarth = 5.98 x 1024 kg Pseawater = 1.03 x 103 kg/m³ Pice = 0.92 x 10³ kg/m³ cos 8 = adj/hyp sin e = opp/hyp a? + b? = c? tan 0 = opp/adj -b ±Vb² – 4ac 2a Ax v = At Δν a = At Δω a = At V = Vọ + at v = vo? + 2a(x-xo) Aw Δt x = Xo + Vot + ½ at? EF = ma T = Fr sin 0 Frr S uN ac = v/r Στ- Ια Fg = w = mg Gm,m2 F Fb = pVsubg Fsp = -kAx r2 p = m/V Vave = (AP r)/8nL P = Po+ pgh P = F/A VIA1 = V2A2=AV/At Pi+pghi+% pv?= P2+pgh2+½ pv,? W = FAr cos 0 KE1+ PE1 = KE2+ PE2 – Wnc P = W/At FAt = Ap Wnet = AKE PEg = mgh KE = % mv? PESP = % k Ax? p = mv E = mc? Momentum T2- T1 = KA = oɛA(T – T) AS = R=L/K Q = mc AT KEave = 3/2 kT Q = mL PV = NkT AU = Q- W W = P AV thermeff = 1-Tc/TH Cannot Start with these but hey are ane) to build to using above Fnet - WMA =MAV/AT Must start with equahon above the line on top and buld from there showing all Steps. and manialaton of formcdas. Fnet AT AmV AP-AmV- Fnet OT
nich then heads m as shown in Figure P7.66. (a) Determine the height h from which cart 1 would need to start to make sure that cart 2 completes the loop without leaving the track. Assume an elastic collision. (b) Find the height needed if instead the more massive cart is allowed to slide down the ramp into the smaller cart. m1 m2 Figure P7.66 Problems 66 and 67. 67. * Again consider the track and carts in Figure P7.66 with = 10 kg and = 20 kg, but this time the carts stick together m1 after the collision. (a) Find the height h from which cart 1 would need to start to make sure that both carts complete the loop without leaving the track. (b) Find the height needed if instead the more massive cart is made to collide with the smaller cart. m2 68. * A block of wood (Mblock face for which the coefficient of kinetic friction is 0.28. A bullet (mbullet becomes stuck in the block. The block plus bullet then slide 87 cm before they come to rest. What was the initial speed of the bullet before impact? 5.2 kg) rests on a horizontal sur- 32 g) is shot along the horizontal direction and quickly %3D 69. * A firefighter directs a horizontal stream of water toward a fire at an angle of 40° measured from the horizontal. The fire hydrant and hose deliver 95 gallons per minute (1 gal/min : 6.31 X 10-4 m³/s), and the nozzle projects the water with a speed of 7.5 m/s. How much horizontal force must the firefighter exert on
Transcribed Image Text:nich then heads m as shown in Figure P7.66. (a) Determine the height h from which cart 1 would need to start to make sure that cart 2 completes the loop without leaving the track. Assume an elastic collision. (b) Find the height needed if instead the more massive cart is allowed to slide down the ramp into the smaller cart. m1 m2 Figure P7.66 Problems 66 and 67. 67. * Again consider the track and carts in Figure P7.66 with = 10 kg and = 20 kg, but this time the carts stick together m1 after the collision. (a) Find the height h from which cart 1 would need to start to make sure that both carts complete the loop without leaving the track. (b) Find the height needed if instead the more massive cart is made to collide with the smaller cart. m2 68. * A block of wood (Mblock face for which the coefficient of kinetic friction is 0.28. A bullet (mbullet becomes stuck in the block. The block plus bullet then slide 87 cm before they come to rest. What was the initial speed of the bullet before impact? 5.2 kg) rests on a horizontal sur- 32 g) is shot along the horizontal direction and quickly %3D 69. * A firefighter directs a horizontal stream of water toward a fire at an angle of 40° measured from the horizontal. The fire hydrant and hose deliver 95 gallons per minute (1 gal/min : 6.31 X 10-4 m³/s), and the nozzle projects the water with a speed of 7.5 m/s. How much horizontal force must the firefighter exert on
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