My teacher gave us these answers but I am wondering how she got the Kinetic Energy? The formula for KE=E-PE but in order to find the total energy you need the kinetic energy so I am confused. Please explain how to do this.
My teacher gave us these answers but I am wondering how she got the Kinetic Energy? The formula for KE=E-PE but in order to find the total energy you need the kinetic energy so I am confused. Please explain how to do this.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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My teacher gave us these answers but I am wondering how she got the Kinetic Energy? The formula for KE=E-PE but in order to find the total energy you need the kinetic energy so I am confused. Please explain how to do this.

Transcribed Image Text:DE=コ574丁
M=T0 kg
KE 1200J
2.
Aim
8. PE =2744 J
KE= A30T E1374J
tm
DE, PE=O
KE= 1374J
E=1374J
PE at point B = 2744J
KE at point B = 4630 I
E at point B= 7374 J
%3D
Mass of object (m) = 70kg
Height@ point A = 9m
Height @point B = 4m
%3D
%3D
B PE = mgh
PE = 70 x9.8×4
PE = 2744 J
Height @point c= 0
KE = E-PE
PE = mgh|
Kinetic Energy + POtenial Energy= TOtal
Formula's
%3D
Energy
%1
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