m, ne N. (a) You are given that limx→ (x log x) = 0 and that limx→ Use L'Hôpital's rule to show that lim [xm (log x)"] X-0 = m lim [xm (log x)"+¹]. n x→0 Hence, by induction or otherwise, show that lim [xm (log x)"] = 0. X→0 (b) with a reduced power or powers in the integrand. (c) Hence compute ¹x6(log x)5 dx. 1 log x 0. Let Manipulate xm (log x)" dx into an integral of similar form but
m, ne N. (a) You are given that limx→ (x log x) = 0 and that limx→ Use L'Hôpital's rule to show that lim [xm (log x)"] X-0 = m lim [xm (log x)"+¹]. n x→0 Hence, by induction or otherwise, show that lim [xm (log x)"] = 0. X→0 (b) with a reduced power or powers in the integrand. (c) Hence compute ¹x6(log x)5 dx. 1 log x 0. Let Manipulate xm (log x)" dx into an integral of similar form but
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 14EQ
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Question
forB
![m, ne N.
(a)
You are given that limx→ (x log x) = 0 and that limx→
Use L'Hôpital's rule to show that
lim [xm (log x)"]
X-0
=
m
lim [xm (log x)"+¹].
n x→0
Hence, by induction or otherwise, show that
lim [xm (log x)"] = 0.
X→0
(b)
with a reduced power or powers in the integrand.
(c)
Hence compute ¹x6(log x)5 dx.
1
log x
0. Let
Manipulate xm (log x)" dx into an integral of similar form but](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc9a962ec-2a54-4cf7-a7d2-7ab3c017237e%2F9af80ff8-e583-4487-a9d3-bbe0752a6a4f%2F8rxwo4xw_processed.png&w=3840&q=75)
Transcribed Image Text:m, ne N.
(a)
You are given that limx→ (x log x) = 0 and that limx→
Use L'Hôpital's rule to show that
lim [xm (log x)"]
X-0
=
m
lim [xm (log x)"+¹].
n x→0
Hence, by induction or otherwise, show that
lim [xm (log x)"] = 0.
X→0
(b)
with a reduced power or powers in the integrand.
(c)
Hence compute ¹x6(log x)5 dx.
1
log x
0. Let
Manipulate xm (log x)" dx into an integral of similar form but
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