Lyman series:nf=1 (91<λ<123 nm; near-UV). Balmer series:nf=2 (365<λ<658 nm; visible). Paschen series:nf=3 (819<λ<1877 nm; near-IR). Brackett series:nf=4 (1.456<λ<4.054 μm; short-to-mid-λ-IR) One of the lines in the emission spectrum of the hydrogen atom has a wavelength of λ = 410.4 nm. Identify the value of nfinal . Identify the value of ninitial.
Lyman series:nf=1 (91<λ<123 nm; near-UV). Balmer series:nf=2 (365<λ<658 nm; visible). Paschen series:nf=3 (819<λ<1877 nm; near-IR). Brackett series:nf=4 (1.456<λ<4.054 μm; short-to-mid-λ-IR) One of the lines in the emission spectrum of the hydrogen atom has a wavelength of λ = 410.4 nm. Identify the value of nfinal . Identify the value of ninitial.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Lyman series:nf=1 (91<λ<123 nm; near-UV). |
Balmer series:nf=2 (365<λ<658 nm; visible). |
Paschen series:nf=3 (819<λ<1877 nm; near-IR). |
Brackett series:nf=4 (1.456<λ<4.054 μm; short-to-mid-λ-IR) |
One of the lines in the emission spectrum of the hydrogen atom has a wavelength of λ = 410.4 nm.
Identify the value of nfinal .
Identify the value of ninitial.
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