n1 = - 2.1787 x 10 18 J n2 = - 0.54468 x 10 18 J - 0,54468 v x 10-18 J n3 = n4 = [ Select ] x 10 18 J etermine the electron transitions, (n¡ nf), that release photons with the following wavelengths (A): • wavelength (A) = 121.57 nm • wavelength (A) = 468.90 nm Calculate the Energy of the photon with a wavelength of: E121.57 nm = [ Select ] x 10-18 J E468.90 nm ( Select ] х 1018 ] Ising the 4 Energy Levels of the Helium Ion, determine the electron transitions, (n¡ → nf), that release the photons with the vavelengths (A) of 121.57 nm and 468.90 nm. 1) = 121.57 nm: ninitial = ( Select ] Nfinal = [ Select ] 1) = 468.90 nm: ninitial = [ Select ] nfinal = [ Select ]
n1 = - 2.1787 x 10 18 J n2 = - 0.54468 x 10 18 J - 0,54468 v x 10-18 J n3 = n4 = [ Select ] x 10 18 J etermine the electron transitions, (n¡ nf), that release photons with the following wavelengths (A): • wavelength (A) = 121.57 nm • wavelength (A) = 468.90 nm Calculate the Energy of the photon with a wavelength of: E121.57 nm = [ Select ] x 10-18 J E468.90 nm ( Select ] х 1018 ] Ising the 4 Energy Levels of the Helium Ion, determine the electron transitions, (n¡ → nf), that release the photons with the vavelengths (A) of 121.57 nm and 468.90 nm. 1) = 121.57 nm: ninitial = ( Select ] Nfinal = [ Select ] 1) = 468.90 nm: ninitial = [ Select ] nfinal = [ Select ]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter7: Atomic Structure And Periodicity
Section: Chapter Questions
Problem 175CP: The figure below represents part of the emission spectrum for a one-electron ion in lhe gas phase....
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![Calculate the electron energies (Eelectron) of the first 4 energy levels in the helium ion (Het+):
v x 10 18 J
- 2.1787
ni =
nɔ =
- 0.54468
x 10-18 J
x 10 18 J
-0.54468
n3 =
n4 =
[ Select ]
x 10-18 J
Determine the electron transitions, (n¡ = nf), that release photons with the following wavelengths (A):
• wavelength (A)
wavelength (A) = 468.90 nm
= 121.57 nm
Calculate the Energy of the photon with a wavelength of:
E121.57 nm
[ Select ]
x 10-18 J
E468.90 nm
[ Select ]
v x 10-18 J
Using the 4 Energy Levels of the Helium Ion, determine the electron transitions, (n; = n;), that release the photons with the
wavelengths (A) of 121.57 nm and 468.90 nm.
(1)
= 121.57 nm:
ninitial =
[ Select ]
nfinal =
[ Select ]
(1)
= 468.90 nm:
Ninitial =
[ Select ]
nfinal =
[ Select ]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F66173c1a-f883-4b2a-9c4a-34112153fb2f%2Fc8ab8d6e-314e-4064-9c59-90e1b1c8a3bc%2Fhpkskng_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the electron energies (Eelectron) of the first 4 energy levels in the helium ion (Het+):
v x 10 18 J
- 2.1787
ni =
nɔ =
- 0.54468
x 10-18 J
x 10 18 J
-0.54468
n3 =
n4 =
[ Select ]
x 10-18 J
Determine the electron transitions, (n¡ = nf), that release photons with the following wavelengths (A):
• wavelength (A)
wavelength (A) = 468.90 nm
= 121.57 nm
Calculate the Energy of the photon with a wavelength of:
E121.57 nm
[ Select ]
x 10-18 J
E468.90 nm
[ Select ]
v x 10-18 J
Using the 4 Energy Levels of the Helium Ion, determine the electron transitions, (n; = n;), that release the photons with the
wavelengths (A) of 121.57 nm and 468.90 nm.
(1)
= 121.57 nm:
ninitial =
[ Select ]
nfinal =
[ Select ]
(1)
= 468.90 nm:
Ninitial =
[ Select ]
nfinal =
[ Select ]
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