Lutomotive engineers have found that the gas mileage in highway riving of a certain sports utility van is normally distributed with mean of 13.6 kilometers per liter and a standard deviation of .5 kilometers per liter. Find the probability that a random sample of 20 sports utility rans has a mean exceeding 14 kilometers per liter. O P(Z > 1.19) = 0.1170 %3D O P (Z > 1.19) 0.8830 %3D O P(Z > –1.19) = 0.8830 O P(Z < -1.19) = 0.1170 %3D
Lutomotive engineers have found that the gas mileage in highway riving of a certain sports utility van is normally distributed with mean of 13.6 kilometers per liter and a standard deviation of .5 kilometers per liter. Find the probability that a random sample of 20 sports utility rans has a mean exceeding 14 kilometers per liter. O P(Z > 1.19) = 0.1170 %3D O P (Z > 1.19) 0.8830 %3D O P(Z > –1.19) = 0.8830 O P(Z < -1.19) = 0.1170 %3D
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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
Transcribed Image Text:Automotive engineers have found that the gas mileage in highway
driving of a certain sports utility van is normally distributed with
a mean of 13.6 kilometers per liter and a standard deviation of
1.5 kilometers per liter.
Find the probability that a random sample of 20 sports utility
vans has a mean exceeding 14 kilometers per liter.
O P(Z > 1.19) = 0.1170
O P(Z > 1.19) = 0.8830
%3D
O P (Z > -1.19) = 0.8830
O P (Z < -1.19) = 0.1170
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