A state school administrator says that the standard deviation Or SAI critical reading test scores is 114. A random sample of 19 SAT critical reading test scores has a standard deviation of 143. At α = 0.10, is there enough evidence to reject the school administrator's claim? Assume the population is normally distributed.
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A: Solution To test the hypothesis we will use t distribution.
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- A national online business magazine reports that the average cost of a speeding ticket in Miami, including court fees, is $220. A local police department claims that this amount has increased. To test their claim, they collect data from a simple random sample of 16 drivers who have been fined for speeding in the last year. Assuming that the distribution of speeding ticket costs is normally distributed and the population standard deviation is $13, is there sufficient evidence to support the police department’s claim at the 0.02 level of significance?A national online business magazine reports that the average cost of a speeding ticket in Miami, including court fees, is $220. A local police department claims that this amount has increased. To test their claim, they collect data from a simple random sample of 16 drivers who have been fined for speeding in the last year. Assuming that the distribution of speeding ticket costs is normally distributed and the population standard deviation is $12, is there sufficient evidence to support the police department’s claim at the 0.01 level of significance? Speeding Ticket Costs in Miami $221 $241 $212 $245 $235 $234 $217 $218 $244 $203 $203 $239 $225 $229 $235 $211 Copy Data Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places. Answer Tables Keypad Keyboard Shortcuts Answer Submit AnswerOn the PSAT test taken by about 1.5 million high school juniors each year, the mean score on the reading portion of the test was 46.9, with a standard deviation of 10.9. The scores are normally distributed. If a student needed a score on this portion of the test that put them in the top 5% of scores nationally to qualify for a particular scholarship, what is the minimum score they must achieve?
- A national online business magazine reports that the average cost of a speeding ticket in Miami, including court fees, is $220. A local police department claims that this amount has increased. To test their claim, they collect data from a simple random sample of 16 drivers who have been fined for speeding in the last year. Assuming that the distribution of speeding ticket costs is normally distributed and the population standard deviation is $14, is there sufficient evidence to support the police department's claim at the 0.02 level of significance? Speeding Ticket Costs in Miami $226 $215 $200 $248 $233 $242 $213 $247 $217 $221 $237 $217 $241 $212 $232 $211 Copy Data Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the United States. Two surveys are conducted. Of the 35 four-year colleges surveyed, the mean enrollment was 5,466 with a standard deviation of 8,191. Of the 35 two-year colleges surveyed, the mean enrollment was 5,068 with a standard deviation of 4,777. Test the student's claim at the 0.10 significance level. a) The null and alternative hypothesis would be: OHO: HF = HT H₁: HF HT O H₁: HF = HT H₁: PF PT t O Ho: PF = PT H₁: PF PT b) Determine the test statistic. Round to two decimals. c) Find the p-value and round to 4 decimals. p= d) Make a decision. O Reject the null hypothesis O Fail to reject the null hypothesis e) Write the conclusion. O There is not sufficient evidence to support the claim that enrollement is high at a four-year college than a two-year college. O There is sufficient evidence to support the claim that enrollement is high at a four-year…A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the United States. Two surveys are conducted. Of the 35 four-year colleges surveyed, the mean enrollment was 5,466 with a standard deviation of 8,191. Of the 35 two-year colleges surveyed, the mean enrollment was 5,068 with a standard deviation of 4,777. Test the student's claim at the 0.10 significance level.a) The null and alternative hypothesis would be: �0:��=���1:��>�� �0:��=���1:��≠�� �0:��=���1:��>�� �0:��=���1:��<�� �0:��=���1:��≠�� �0:��=���1:��<�� b) Determine the test statistic. Round to two decimals.�=c) Find the p-value and round to 4 decimals.p =
- A public bus company official claims that the mean waiting time for Bus # 14 during peak hours is approximately 10 minutes. Karen took Bus # 14 during peak hours on 36 different occasions. Her mean waiting time was 8.7 minutes. Assume that the population standard deviation o of 2.9 minutes is known. At the 0.01 significance level, test if the mean of all the peak hours waiting time for Bus # 14 is significantly different from 10 minutes.Pilots who cannot maintain regular sleep hours due to their work schedule often suffer from insomnia. A recent study on sleeping patterns of pilots focused on quantifying deviations from regular sleep hours. A random sample of 28 commercial airline pilots was interviewed, and the pilots in the sample reported the time at which they went to sleep on their most recent working day. The study gave the sample mean and standard deviation of the times reported by pilots, with these times measured in hours after midnight. (Thus, if the pilot reported going to sleep at p.m., the measurement was -1.) The sample mean was 0.8 hours, and the standard deviation was 1.6 hours. Assume that the sample is drawn from a normally distributed population. Find a 90% confidence interval for the population standard deviation, that is, the standard deviation of the time (hours after midnight) at which pilots go to sleep on their work days. Then give its lower limit and upper limit.The breaking strengths of cables produced by a certain manufacturer have historically had a mean of 1775 pounds and a standard deviation of 70 pounds. The Español company believes that, due to an improvement in the manufacturing process, the mean breaking strength, µ, of the cables is now greater than 1775 pounds. To see if this is the case, 16 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1806 pounds. Assume that the population is normally distributed. Can we support, at the 0.10 level of significance, the claim that the population mean breaking strength of the newly- manufactured cables is greater than 1775 pounds? Assume that the population standard deviation has not changed. Perform a one-tailed test. Then complete the parts below. 00 Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis H,…
- In a school district, all sixth grade students take the same standardized test. The superintendant of the school district takes a random sample of 3030 scores from all of the students who took the test. She sees that the mean score is 169169 with a standard deviation of 7.06747.0674. The superintendant wants to know if the standard deviation has changed this year. Previously, the population standard deviation was 1313. Is there evidence that the standard deviation of test scores has decreased at the α=0.005α=0.005 level? Assume the population is normally distributed. Step 1 of 5: State the null and alternative hypotheses. Round to four decimal places when necessary. Step 2 of 5: Determine the critical value(s) of the test statistic. If the test is two-tailed, separate the values with a comma. Round your answer to three decimal places. Step 3 of 5: Determine the value of the test statistic. Round your answer to three decimal places. Step 4 of 5: Make the…The Ankle Brachial Index (ABI) compares the blood pressure of a patient's arm to the blood pressure of the patient's leg. A healthy ABI is 0.9 or greater. In a study, researchers obtained the ABI of 187 women with arterial disease. The results were a mean ABI of 0.86 with a standard deviation of 0.16. At the 1% significance level, do the data provide sufficient evidence to conclude that, on average, women with arterial disease have an unhealthy ABI? Set up the hypotheses for the one-mean t-test. Hou Ha: HIn a certain country the heights of adult men are normally distributed with a mean of 70.2 inches and a standard deviation of 2.7 inches. The country's military requires that men have heights between 66 inches and 79 inches. Determine what percentage of this country's men are eligible for the military based on height. The percentage of men that are eligible for the military based on height is nothing%. (Round to two decimal places as needed.)