A director of student success wants to test whether currently enrolled students study more than 3 hours per day on average. A random sample of 25 students has a mean study time of 3.32 hours with a sample standard deviation of 0.80 hour. At a = 0.05, does this sample provide convincing evidence that students study more than 3 hours per day on average? Assume that study time is normally distributed.
A director of student success wants to test whether currently enrolled students study more than 3 hours per day on average. A random sample of 25 students has a mean study time of 3.32 hours with a sample standard deviation of 0.80 hour. At a = 0.05, does this sample provide convincing evidence that students study more than 3 hours per day on average? Assume that study time is normally distributed.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A director of student success wants to test whether currently enrolled students study more than 3 hours per day on average. A random sample of
25 students has a mean study time of 3.32 hours with a sample standard deviation of 0.80 hour. At a = 0.05, does this sample provide
convincing evidence that students study more than 3 hours per day on average? Assume that study time is normally distributed.
Ho: μ ≥ 3.32 Ha: μ<3.32. Test statistic t = -2.00. Rejection region: t > 1.711. Do not reject Ho. There is not sufficient evidence to conclude
that students study more than 3 hours per day on average.
Ho: μ≤3 Ha: μ> 3. Test statistic t = 2.00. Rejection region: t > 1.711. Reject Ho. There is sufficient evidence to conclude that students
study more than 3 hours per day on average.
Ho: μ ≥ 3 H₂: μ<3. Test statistic t = -2.00. Rejection region: t < -1.711. Reject Ho. There is sufficient evidence to conclude that students
study more than 3 hours per day on average.
Ho: u≤3.32 Ha: μ> 3.32. Test statistic t = 2.00. Rejection region: t < -1.711. Do not reject Ho. There is not sufficient evidence to conclude
that students study more than 3 hours per day on average.
Ho: μ ≥3 H₂: μ< 3. Test statistic t = -2.00. Rejection region: t < -1.711. Do not reject Ho. There is not sufficient evidence to conclude that
students study more than 3 hours per day on average.
Ho: μ≤ 3 H₂: μ> 3. Test statistic t = 2.00. Rejection region: t > 1.711. Do not reject Ho. There is not sufficient evidence to conclude that
students study more than 3 hours per day on average.
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